'''
只要判断字符中相反的路径,比如R和L,U和D的出现次数是否相等即可
'''
class Solution:
def judgeCircle(self, moves):
numR = moves.count('R')
numL = moves.count('L')
numU = moves.count('U')
numD = moves.count('D')
if numR == numL and numU == numD:
return True
else:
return False