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If following the math background of your source, they compute the output layer delta (in your case dz2) as δx,L=∇aCx⊙σ′(zx,L), which should be translated to your code as:
Sorry? you have send your messege to wrong e-майл, re-send it to write man/
Goog luck !
Воскресенье, 16 августа 2020, 18:40 +03:00 от jEzEk ***@***.***>:
Hello. Investigating your blog, I've stumbled upon this line in training function:
https://github.com/Frixoe/xor-neural-network/blob/af6eda3f8bb25e5a5f2e6f062a3a0e7080af2491/XOR-Net-Notebook.ipynb#L433
If following the math background of your source , they compute the output layer delta (in your case dz2) as δx,L=∇aCx⊙σ′(zx,L), which should be translated to your code as:
dz2 = np.multiply(a2 - y[j], sigmoid(a2, derv=True)) # 1x1 .* 1x1 = 1x1
Or am I missing something?
Thank you for your time (and repo) and I'm looking forward for your answer.
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Sorry? you have send your messege to wrong e-майл, re-send it to write man/ Goog luck !
I did not send email. I wrote an issue to @Frixoe github repo xor-neural-network. Maybe you are watching the repository and you got notification from github to your email.
Thank you for your concerns and have a nice life. 😉
Hello. Investigating your blog, I've stumbled upon this line in training function:
xor-neural-network/XOR-Net-Notebook.ipynb
Line 433 in af6eda3
If following the math background of your source, they compute the output layer delta (in your case
dz2
) asδx,L=∇aCx⊙σ′(zx,L)
, which should be translated to your code as:Or am I missing something?
Thank you for your time (and repo) and I'm looking forward for your answer.
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