Let A be the set of properties which are not sharing column with any principal.
B be the subset of A where property is required.
C be subset of A where property is optional. (hence A = B + C)

The necessary condition for materialization without anything else be C1 - all required properties (excluding PK) must have a value (with or without sharing).
- If A is empty, then C1 will be sufficient condition as it will be required dependent.
- If B is non-empty, then C1 will cover those properties and be sufficient condition.
- If B is empty and then C is non-empty, then materialize if there is at least 1 non-null value in C along with C1 being true.
- Otherwise null.

If there are no required properties other than PK (essentially C1 does not exist). B is by definition empty.
- If A is empty then always materialize.
- If A is non-empty implies C is non-empty, then materialize if there is at least 1 non-null value in C.

Resolves #22054

Co-authored-by: Andriy Svyryd <AndriySvyryd@users.noreply.github.com>