MinVersion failing for '^2.16.2 ^2.16' alike range

Patch for issue #340

EDIT(@isaacs): updated to make it not break other stuff, and added test.

PR-URL: #341
Credit: @alfredsgenkins
Close: #341
Reviewed-by: @isaacs

ranges/min-version.js

@@ -19,6 +19,7 @@ const minVersion = (range, loose) => {
   for (let i = 0; i < range.set.length; ++i) {
     const comparators = range.set[i]
 
+    let setMin = null
     comparators.forEach((comparator) => {
       // Clone to avoid manipulating the comparator's semver object.
       const compver = new SemVer(comparator.semver.version)
@@ -33,8 +34,8 @@ const minVersion = (range, loose) => {
           /* fallthrough */
         case '':
         case '>=':
-          if (!minver || gt(minver, compver)) {
-            minver = compver
+          if (!setMin || gt(compver, setMin)) {
+            setMin = compver
           }
           break
         case '<':
@@ -46,6 +47,8 @@ const minVersion = (range, loose) => {
           throw new Error(`Unexpected operation: ${comparator.operator}`)
       }
     })
+    if (setMin && (!minver || gt(minver, setMin)))
+      minver = setMin
   }
 
   if (minver && range.test(minver)) {

test/ranges/min-version.js

@@ -33,6 +33,7 @@ test('minimum version in range tests', (t) => {
     ['^1.1.1', '1.1.1'],
     ['^1.1.1-beta', '1.1.1-beta'],
     ['^1.1.1 || >=2', '1.1.1'],
+    ['^2.16.2 ^2.16', '2.16.2'],
 
     // '-' operator
     ['1.1.1 - 1.8.0', '1.1.1'],
@@ -69,7 +70,10 @@ test('minimum version in range tests', (t) => {
     const loose = tuple[2] || false
     const msg = `minVersion(${range}, ${loose}) = ${version}`
     const min = minVersion(range, loose)
-    t.ok(min === version || (min && min.version === version), msg)
+    t.ok(min === version || (min && min.version === version), msg, {
+      found: min,
+      wanted: version,
+    })
   })
   t.end()
 })