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Turning on Idempotent Producer doubles the latency #5054
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Kafka protocol is asynchronous: a client may send the next write request without waiting for the previous request to finish. Since Redpanda's Raft implementation is also asynchronous, it's possible to process Kafka requests with minimal overhead and/or delays. The challenge is to process causally related requests without pipeline stalling. Imagine that we have two requests A and B. When we want to process them as fast as possible we should start repli- cating the latter request without waiting until the replication of the first request is over. But in case the requests are the RSM commands and are causally related e.g. request A is "set x=2" and B is "set y=3 if x=2" then to guarantee that B's precondition holds Redpanda can't start replication of B request without knowing that - The request A is successfully executed - No other command sneaks in between A and B In case of idempotency the condition we need to preserve is the monotonicity of the seq numbers without gaps. In order to preserve causality and to avoid pipeline stalls we use optimistic replication. A leader knows about its ongoing operations so it may optimistically predict the outcome of operation A and start executing operation B assuming its prediction is true. But what happens if Redpanda is wrong with its prediction, how does it ensure safety? Let's break down all the failure scenarios. A leader uses a mutex and consesnsus::replicate_in_stages order all the incoming requests. Before the first stage is resolves the mutex controls the order and after the first stage is resolved Redpanda's raft implementation guarantees order: auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(request); co_await stages.enqueued; u.return_all(); // after this point the order between the requests is certain // the order enforced by mutex is preserved in the log The mutex / replicate_in_stages combination may enforce partial order but can't prevent out-of-nowhere writes. Imagine a node loses the leadership then new leader inserts a command C and transfers the leadership back to the original node. To fight this Redpanda uses conditional replication: auto term = persisted_stm::sync(); auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(term, request); co_await stages.enqueued; u.return_all(); It uses a sync method to make sure that the RSM's state reflects all the commands replicated by previous term (during this phase it may learn about the "A" command) and then it uses the raft's term to issue the replication command (conditional replicate). By design the replication call can't succeed if the term is wrong so instead of leading the ACB state the replication of B is doomed to fail. Redpanda's Raft implementation guarantees that if A was enqueued before B within the same term then the replication of B can't be successful without replication of A so we may not worry that A may be dropped. But we still have uncertainty. Should Redpanda process B assuming that A was successful or should it assume it failed? In order to resolve the uncertainty the leader steps down. Since sync() guarantees that the RSM's state reflects all the commands replicated by previous term - the next leader will resolve the uncertainty. The combination of those methods lead to preserving causal relationships between the requests (idempotency) without introducing pipelining stalls. ------------------------------------------------------------------- The idempotency logic is straightforward: - Take a lock identified by producer id (concurrent producers don't affect each other) - If the seq number and its offset is already known then return the offset - If the seq number is known and in flight then "park" the current request (once the original resolved it pings all the parked requests with the written offsets or an error) - If the seq number is seen for the first time then: - Reject it if there is a gap between it and the last known seq - Start processing if there is no gap fixes redpanda-data#5054
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Kafka protocol is asynchronous: a client may send the next write request without waiting for the previous request to finish. Since Redpanda's Raft implementation is also asynchronous, it's possible to process Kafka requests with minimal overhead and/or delays. The challenge is to process causally related requests without pipeline stalling. Imagine that we have two requests A and B. When we want to process them as fast as possible we should start repli- cating the latter request without waiting until the replication of the first request is over. But in case the requests are the RSM commands and are causally related e.g. request A is "set x=2" and B is "set y=3 if x=2" then to guarantee that B's precondition holds Redpanda can't start replication of B request without knowing that - The request A is successfully executed - No other command sneaks in between A and B In case of idempotency the condition we need to preserve is the monotonicity of the seq numbers without gaps. In order to preserve causality and to avoid pipeline stalls we use optimistic replication. A leader knows about its ongoing operations so it may optimistically predict the outcome of operation A and start executing operation B assuming its prediction is true. But what happens if Redpanda is wrong with its prediction, how does it ensure safety? Let's break down all the failure scenarios. A leader uses a mutex and consesnsus::replicate_in_stages order all the incoming requests. Before the first stage is resolves the mutex controls the order and after the first stage is resolved Redpanda's raft implementation guarantees order: auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(request); co_await stages.enqueued; u.return_all(); // after this point the order between the requests is certain // the order enforced by mutex is preserved in the log The mutex / replicate_in_stages combination may enforce partial order but can't prevent out-of-nowhere writes. Imagine a node loses the leadership then new leader inserts a command C and transfers the leadership back to the original node. To fight this Redpanda uses conditional replication: auto term = persisted_stm::sync(); auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(term, request); co_await stages.enqueued; u.return_all(); It uses a sync method to make sure that the RSM's state reflects all the commands replicated by previous term (during this phase it may learn about the "A" command) and then it uses the raft's term to issue the replication command (conditional replicate). By design the replication call can't succeed if the term is wrong so instead of leading the ACB state the replication of B is doomed to fail. Redpanda's Raft implementation guarantees that if A was enqueued before B within the same term then the replication of B can't be successful without replication of A so we may not worry that A may be dropped. But we still have uncertainty. Should Redpanda process B assuming that A was successful or should it assume it failed? In order to resolve the uncertainty the leader steps down. Since sync() guarantees that the RSM's state reflects all the commands replicated by previous term - the next leader will resolve the uncertainty. The combination of those methods lead to preserving causal relationships between the requests (idempotency) without introducing pipelining stalls. ------------------------------------------------------------------- The idempotency logic is straightforward: - Take a lock identified by producer id (concurrent producers don't affect each other) - If the seq number and its offset is already known then return the offset - If the seq number is known and in flight then "park" the current request (once the original resolved it pings all the parked requests with the written offsets or an error) - If the seq number is seen for the first time then: - Reject it if there is a gap between it and the last known seq - Start processing if there is no gap fixes redpanda-data#5054
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Kafka protocol is asynchronous: a client may send the next write request without waiting for the previous request to finish. Since Redpanda's Raft implementation is also asynchronous, it's possible to process Kafka requests with minimal overhead and/or delays. The challenge is to process causally related requests without pipeline stalling. Imagine that we have two requests A and B. When we want to process them as fast as possible we should start repli- cating the latter request without waiting until the replication of the first request is over. But in case the requests are the RSM commands and are causally related e.g. request A is "set x=2" and B is "set y=3 if x=2" then to guarantee that B's precondition holds Redpanda can't start replication of B request without knowing that - The request A is successfully executed - No other command sneaks in between A and B In case of idempotency the condition we need to preserve is the monotonicity of the seq numbers without gaps. In order to preserve causality and to avoid pipeline stalls we use optimistic replication. A leader knows about its ongoing operations so it may optimistically predict the outcome of operation A and start executing operation B assuming its prediction is true. But what happens if Redpanda is wrong with its prediction, how does it ensure safety? Let's break down all the failure scenarios. A leader uses a mutex and consesnsus::replicate_in_stages order all the incoming requests. Before the first stage is resolves the mutex controls the order and after the first stage is resolved Redpanda's raft implementation guarantees order: auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(request); co_await stages.enqueued; u.return_all(); // after this point the order between the requests is certain // the order enforced by mutex is preserved in the log The mutex / replicate_in_stages combination may enforce partial order but can't prevent out-of-nowhere writes. Imagine a node loses the leadership then new leader inserts a command C and transfers the leadership back to the original node. To fight this Redpanda uses conditional replication: auto term = persisted_stm::sync(); auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(term, request); co_await stages.enqueued; u.return_all(); It uses a sync method to make sure that the RSM's state reflects all the commands replicated by previous term (during this phase it may learn about the "A" command) and then it uses the raft's term to issue the replication command (conditional replicate). By design the replication call can't succeed if the term is wrong so instead of leading the ACB state the replication of B is doomed to fail. Redpanda's Raft implementation guarantees that if A was enqueued before B within the same term then the replication of B can't be successful without replication of A so we may not worry that A may be dropped. But we still have uncertainty. Should Redpanda process B assuming that A was successful or should it assume it failed? In order to resolve the uncertainty the leader steps down. Since sync() guarantees that the RSM's state reflects all the commands replicated by previous term - the next leader will resolve the uncertainty. The combination of those methods lead to preserving causal relationships between the requests (idempotency) without introducing pipelining stalls. ------------------------------------------------------------------- The idempotency logic is straightforward: - Take a lock identified by producer id (concurrent producers don't affect each other) - If the seq number and its offset is already known then return the offset - If the seq number is known and in flight then "park" the current request (once the original resolved it pings all the parked requests with the written offsets or an error) - If the seq number is seen for the first time then: - Reject it if there is a gap between it and the last known seq - Start processing if there is no gap fixes redpanda-data#5054
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Kafka protocol is asynchronous: a client may send the next write request without waiting for the previous request to finish. Since Redpanda's Raft implementation is also asynchronous, it's possible to process Kafka requests with minimal overhead and/or delays. The challenge is to process causally related requests without pipeline stalling. Imagine that we have two requests A and B. When we want to process them as fast as possible we should start repli- cating the latter request without waiting until the replication of the first request is over. But in case the requests are the RSM commands and are causally related e.g. request A is "set x=2" and B is "set y=3 if x=2" then to guarantee that B's precondition holds Redpanda can't start replication of B request without knowing that - The request A is successfully executed - No other command sneaks in between A and B In case of idempotency the condition we need to preserve is the monotonicity of the seq numbers without gaps. In order to preserve causality and to avoid pipeline stalls we use optimistic replication. A leader knows about its ongoing operations so it may optimistically predict the outcome of operation A and start executing operation B assuming its prediction is true. But what happens if Redpanda is wrong with its prediction, how does it ensure safety? Let's break down all the failure scenarios. A leader uses a mutex and consesnsus::replicate_in_stages order all the incoming requests. Before the first stage is resolves the mutex controls the order and after the first stage is resolved Redpanda's raft implementation guarantees order: auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(request); co_await stages.enqueued; u.return_all(); // after this point the order between the requests is certain // the order enforced by mutex is preserved in the log The mutex / replicate_in_stages combination may enforce partial order but can't prevent out-of-nowhere writes. Imagine a node loses the leadership then new leader inserts a command C and transfers the leadership back to the original node. To fight this Redpanda uses conditional replication: auto term = persisted_stm::sync(); auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(term, request); co_await stages.enqueued; u.return_all(); It uses a sync method to make sure that the RSM's state reflects all the commands replicated by previous term (during this phase it may learn about the "A" command) and then it uses the raft's term to issue the replication command (conditional replicate). By design the replication call can't succeed if the term is wrong so instead of leading the ACB state the replication of B is doomed to fail. Redpanda's Raft implementation guarantees that if A was enqueued before B within the same term then the replication of B can't be successful without replication of A so we may not worry that A may be dropped. But we still have uncertainty. Should Redpanda process B assuming that A was successful or should it assume it failed? In order to resolve the uncertainty the leader steps down. Since sync() guarantees that the RSM's state reflects all the commands replicated by previous term - the next leader will resolve the uncertainty. The combination of those methods lead to preserving causal relationships between the requests (idempotency) without introducing pipelining stalls. ------------------------------------------------------------------- The idempotency logic is straightforward: - Take a lock identified by producer id (concurrent producers don't affect each other) - If the seq number and its offset is already known then return the offset - If the seq number is known and in flight then "park" the current request (once the original resolved it pings all the parked requests with the written offsets or an error) - If the seq number is seen for the first time then: - Reject it if there is a gap between it and the last known seq - Start processing if there is no gap fixes redpanda-data#5054
/backport v22.1.x |
rystsov
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Kafka protocol is asynchronous: a client may send the next write request without waiting for the previous request to finish. Since Redpanda's Raft implementation is also asynchronous, it's possible to process Kafka requests with minimal overhead and/or delays. The challenge is to process causally related requests without pipeline stalling. Imagine that we have two requests A and B. When we want to process them as fast as possible we should start repli- cating the latter request without waiting until the replication of the first request is over. But in case the requests are the RSM commands and are causally related e.g. request A is "set x=2" and B is "set y=3 if x=2" then to guarantee that B's precondition holds Redpanda can't start replication of B request without knowing that - The request A is successfully executed - No other command sneaks in between A and B In case of idempotency the condition we need to preserve is the monotonicity of the seq numbers without gaps. In order to preserve causality and to avoid pipeline stalls we use optimistic replication. A leader knows about its ongoing operations so it may optimistically predict the outcome of operation A and start executing operation B assuming its prediction is true. But what happens if Redpanda is wrong with its prediction, how does it ensure safety? Let's break down all the failure scenarios. A leader uses a mutex and consesnsus::replicate_in_stages order all the incoming requests. Before the first stage is resolves the mutex controls the order and after the first stage is resolved Redpanda's raft implementation guarantees order: auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(request); co_await stages.enqueued; u.return_all(); // after this point the order between the requests is certain // the order enforced by mutex is preserved in the log The mutex / replicate_in_stages combination may enforce partial order but can't prevent out-of-nowhere writes. Imagine a node loses the leadership then new leader inserts a command C and transfers the leadership back to the original node. To fight this Redpanda uses conditional replication: auto term = persisted_stm::sync(); auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(term, request); co_await stages.enqueued; u.return_all(); It uses a sync method to make sure that the RSM's state reflects all the commands replicated by previous term (during this phase it may learn about the "A" command) and then it uses the raft's term to issue the replication command (conditional replicate). By design the replication call can't succeed if the term is wrong so instead of leading the ACB state the replication of B is doomed to fail. Redpanda's Raft implementation guarantees that if A was enqueued before B within the same term then the replication of B can't be successful without replication of A so we may not worry that A may be dropped. But we still have uncertainty. Should Redpanda process B assuming that A was successful or should it assume it failed? In order to resolve the uncertainty the leader steps down. Since sync() guarantees that the RSM's state reflects all the commands replicated by previous term - the next leader will resolve the uncertainty. The combination of those methods lead to preserving causal relationships between the requests (idempotency) without introducing pipelining stalls. ------------------------------------------------------------------- The idempotency logic is straightforward: - Take a lock identified by producer id (concurrent producers don't affect each other) - If the seq number and its offset is already known then return the offset - If the seq number is known and in flight then "park" the current request (once the original resolved it pings all the parked requests with the written offsets or an error) - If the seq number is seen for the first time then: - Reject it if there is a gap between it and the last known seq - Start processing if there is no gap fixes redpanda-data#5054 (cherry picked from commit 88423d7) (cherry picked from commit 00e4118ad3f711d2a527faf2d28d4c580421b447)
rystsov
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Kafka protocol is asynchronous: a client may send the next write request without waiting for the previous request to finish. Since Redpanda's Raft implementation is also asynchronous, it's possible to process Kafka requests with minimal overhead and/or delays. The challenge is to process causally related requests without pipeline stalling. Imagine that we have two requests A and B. When we want to process them as fast as possible we should start repli- cating the latter request without waiting until the replication of the first request is over. But in case the requests are the RSM commands and are causally related e.g. request A is "set x=2" and B is "set y=3 if x=2" then to guarantee that B's precondition holds Redpanda can't start replication of B request without knowing that - The request A is successfully executed - No other command sneaks in between A and B In case of idempotency the condition we need to preserve is the monotonicity of the seq numbers without gaps. In order to preserve causality and to avoid pipeline stalls we use optimistic replication. A leader knows about its ongoing operations so it may optimistically predict the outcome of operation A and start executing operation B assuming its prediction is true. But what happens if Redpanda is wrong with its prediction, how does it ensure safety? Let's break down all the failure scenarios. A leader uses a mutex and consesnsus::replicate_in_stages order all the incoming requests. Before the first stage is resolves the mutex controls the order and after the first stage is resolved Redpanda's raft implementation guarantees order: auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(request); co_await stages.enqueued; u.return_all(); // after this point the order between the requests is certain // the order enforced by mutex is preserved in the log The mutex / replicate_in_stages combination may enforce partial order but can't prevent out-of-nowhere writes. Imagine a node loses the leadership then new leader inserts a command C and transfers the leadership back to the original node. To fight this Redpanda uses conditional replication: auto term = persisted_stm::sync(); auto u = co_await mutex.lock(); auto stages = raft.replicate_in_stages(term, request); co_await stages.enqueued; u.return_all(); It uses a sync method to make sure that the RSM's state reflects all the commands replicated by previous term (during this phase it may learn about the "A" command) and then it uses the raft's term to issue the replication command (conditional replicate). By design the replication call can't succeed if the term is wrong so instead of leading the ACB state the replication of B is doomed to fail. Redpanda's Raft implementation guarantees that if A was enqueued before B within the same term then the replication of B can't be successful without replication of A so we may not worry that A may be dropped. But we still have uncertainty. Should Redpanda process B assuming that A was successful or should it assume it failed? In order to resolve the uncertainty the leader steps down. Since sync() guarantees that the RSM's state reflects all the commands replicated by previous term - the next leader will resolve the uncertainty. The combination of those methods lead to preserving causal relationships between the requests (idempotency) without introducing pipelining stalls. ------------------------------------------------------------------- The idempotency logic is straightforward: - Take a lock identified by producer id (concurrent producers don't affect each other) - If the seq number and its offset is already known then return the offset - If the seq number is known and in flight then "park" the current request (once the original resolved it pings all the parked requests with the written offsets or an error) - If the seq number is seen for the first time then: - Reject it if there is a gap between it and the last known seq - Start processing if there is no gap fixes redpanda-data#5054 (cherry picked from commit 88423d7)
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Version & Environment
Redpanda version: (use
rpk version
):v22.1.3 compared with v21.11.16
What went wrong?
By default, v22.1 is double the latency of v21.11. This seems to be due to idempotent producers, as when this is turned off we see that the latency of v22.1 is reduced to that of what was seen in v21.11.
What should have happened instead?
There should be no additional latency added when using an idempotent producer.
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