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A macro named default can't be called in an impl #42292

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qnighy opened this issue May 29, 2017 · 0 comments
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A macro named default can't be called in an impl #42292

qnighy opened this issue May 29, 2017 · 0 comments
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A-parser Area: The parsing of Rust source code to an AST.

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@qnighy
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qnighy commented May 29, 2017

There is a corner case where the weak (contextual) keyword default can't be used in an identifier position. It occurs when a macro whose path starts with default is called inside an impl.

macro_rules! foo {
    ($($x:tt)*) => { $($x)* }
}
macro_rules! default {
    ($($x:tt)*) => { $($x)* }
}

struct A;
impl A {
    foo! { fn bar() {} }
    default! { fn baz() {} } // ERROR
}

fn main() {
    A::bar();
    A::baz();
}

Expected behavior: it compiles.

Observed behavior: parse error.

Version: rustc 1.19.0-nightly (28fd1e519 2017-05-27)

@petrochenkov petrochenkov added the A-parser Area: The parsing of Rust source code to an AST. label May 29, 2017
Mark-Simulacrum added a commit to Mark-Simulacrum/rust that referenced this issue May 31, 2017
…chenkov

Parse macros named "default" correctly.

Fixes rust-lang#42292.
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Labels
A-parser Area: The parsing of Rust source code to an AST.
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