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Berikut ini pemetaan (mapping) formasi angka Limapuluh Delapan (58) ke piramida data dari diagram berupa konsep, detil bagan dan modul² yang dipakai sebagai dasar pemrograman.
Pada projek ini angka 58 berfungsi untuk merepresentasikan Bagan Sequence. Pada halaman ini kita akan bahas detil bagaimana fungsi ini dijalankan.
Secara singkat skema yang akan dijalankan oleh Bagan Sequence adalah formasi 10 ke 29 pada Skema P(7):142857 yang dibahas pada angka delapan belas (18).
Proses dari 10 dan 58 ini berujung di vektor 68 ke 71. Ini yang akan kita bahas. Sebelum masuk ke detail, berikut ini daftar keistimewaan angka 58 menurut wikipedia:
- Lima puluh delapan adalah jumlah dari tujuh bilangan prima pertama, bilangan 11 gonal, dan bilangan Smith
- Diberikan 58, fungsi Mertens mengembalikan 0
- Tidak ada solusi untuk persamaan x - φ ( x ) = 58, menjadikan 58 nonototient
- Namun, jumlah fungsi total untuk tiga belas bilangan bulat pertama adalah 58.
- Simak untuk keistimewaan² lainnya.
Pola angka ini terdiri dari tiga (3) elemen utama dimana ada empat (4) elemen pada urutan yang pertama yang merupakan representasi angka ke-2 dari Skema P(7):1,4,2,8,5,7.
id:58
---+-----+-----+
1 | 1 | {4} | 4¤
---+-----+-----+ } 13¤
2 | {5} | 13 | 9¤ } 31¤
---+-----+-----+ } 18¤
3 | 14 |{22} | 9¤
---+-----+-----+Pola istimewa yang ada pada angka id 58 ini adalah bertemunya kembali angka 8 dan 5 antara komposisi dan polaritas dimana gabungan angkanya yaitu 85 merupakan mirror dari id.
---+-----+-----+-----+-----+
1 | 3 | 1 | 4 | 5 |----------
---+-----+-----+-----+-----+ |
2 | {8} | {5} | 13 | 18 |-- {8} {5}
---+-----+-----+-----+-----+ |
3 | 8 | 14 | 22 | 36 |----------
---+-----+-----+-----+-----+Secara umum diketahui bahwa keistimewaan 58 adalah jumlah tujuh (7) bilangan prima pertama. Namun jumlah 22 Objek merupakan elemen yang menunjukan karakter sebenarnya dari angka ini.
- 58 is a Hoax Number. 58 reversed (85) is a Hoax Number and 85 = 5 x 17.
- Note that 5 x 71 = 355 is also a Hoax Number.
- A composite number defined analogously to a Smith Number except that the sum of the number's digits equals the sum of the digits of its distinct prime factors (excluding 1).
- The first few hoax numbers are 22, 58, 84, 85, 94, 136, 160, 166, 202, 234, ... (OEIS A019506), illustrated above as a binary plot, and the corresponding sums of digits are 4, 13, 12, 13, 13, 10, 7, 13, 4, 9, 7, ... (OEIS A050223).
Maka angka 22 merupakan unsur penting sehingga polanya kita bagi menjadi empat (4) bagian yang terdiri dari elemen 4 vs 18 dimana angka empat (4) mewakili id: 57 dari Flowchart:
Hasilnya akan berupa format P(7):142857 dimana unit pertama bergabung dengan 4 ke (1,5) vs 18 ke (3,6,9) yang akan dijalankan ke format (28,29) sehingga berujung 57 seperti berikut:
Alurnya akan ada tujuh (7) yaitu alur 1 sd 6 berikut alur 1 ke 2 dari 57 ke 60 via format (1,3) yang jatuh di angka 2 dan 60 sebagai formasi awal dari proses selanjutnya di id: 59.
Karena objeknya ada 22 maka 7 alur ini akan mewakili 227 objek dari angka 26 hingga berujung ke 286 objek dari angka dua (2) via 165 objek dari angka enam (6).
Angka 26 merupakan proyeksi dari angka 2 dan 6 maka selisih 227 ke 286 objek dari angka dua (2) ada di angka 59 ke 60 akan tampil di id: 4.
id: 4
---+-----+-----
1 | {1} |{43}
---+-----+-----
2 | 44 |{57}
---+-----+-----
3 |{58} |{59}
---+-----+-----
4 |{60} | 104
---+-----+-----
5 | 105 |{115}
---+-----+-----
6 |{116}| 134
---+-----+-----
7 | 135 | 162
---+-----+-----
8 | 163 | 175
---+-----+-----
9 | 176 |{176}
---+-----+-----Separasi antara 4 ke 22 mengantar skema (3,6,9) dari id: 18 menjadi dominan. Dengan demikian proses dari tujuh (7) alur dapat diuraikan dalam format 1 vs 6:
id: 18
---+-----+-----
1 | 1 | 5 ----
---+-----+----- |
2 | 6 | 8 |
---+-----+----- | 2nd Δ400
3 | 9 |{26} |
---+-----+----- | } 431
4 |{27} | 28 --3-¤
---+-----+----- | 3rd Δ31
5 | 29 | 31 ----
---+-----+-----
6 | 32 | 32 ----
---+-----+----- |
7 | 33 | 44 |
---+-----+----- | 4th Δ400
8 | 45 | 46 |
---+-----+----- | } 500
9 | 47 |{49} --6-¤
---+-----+----- | 5th Δ100
10 |{50} | 50 ----
---+-----+----- } 538
11 | 51 | 53 ----
---+-----+----- |
12 | 54 | 59 |
---+-----+----- | 6th Φ83 = 38
13 | 60 | 82 |
---+-----+----- |
14 | 83 |{102} --9-¤
---+-----+----- | 7th Φ102 = 201
15 |{103}| 110 ----
---+-----+-----Kedua formasi ini akan bergabung di Bagan Sequence sehingga memunculkan konfigurasi dari angka (2) yang merepresentasikan ujung framing dari seluruh objek dari 114 angka dasar.
- 176 + 110 = 286 = 22 x 13
id: 2
---+-----+-----+-----+-----+
1 |{19} | 1 |{20} | 21 |-----------------------
---+-----+-----+-----+-----+ |
2 | 18 | 21 | 39 | 60 |----------------- |
---+-----+-----+-----+-----+ | |
3 | 63 | 40 | 103 |{143}|----------- | |
---+-----+-----+-----+-----+ | | |
4 | 37 | 104 | 141 | 245 |----- | | |
---+-----+-----+-----+-----+ | | | |
5 | 10 | 142 | 152 | 294 |-{10}|{13} |{12} |{12} |{18}
---+-----+-----+-----+-----+ | | | |
6 | 24 | 153 |{177}| 332 |----- | | |
---+-----+-----+-----+-----+ | | |
7 | 75 | 178 | 253 | 431 |----------- | |
---+-----+-----+-----+-----+ | |
8 | 30 | 254 | 284 | 538 |----------------- |
---+-----+-----+-----+-----+ |
9 | 1 | 285 | 286 |{571}|-----------------------
===+=====+=====+=====+=====+
45 |{277}|
---+-----+Prosesnya dilakukan dengan menggunakan skema dari angka 26 sebagai representasidari angka dua (2) dan enam (6). Disini Anda lihat posisi id: 58 dibawa ke angka 100.
- 5 + 2 + 58 + 35 = 5 + 60 + 35 = 65 + 35 = 100
id: 26
---+-----+-----+-----+-----+
1 | {5}| 1 | 6 | 7 |----------------------------
---+-----+-----+-----+-----+ |
2 | {2}| 7 | 9 | 16 |---------------------- |
---+-----+-----+-----+-----+ | |
3 | {58}| 10 | 68 | 78 |---------------- | |
---+-----+-----+-----+-----+ | | |
4 | {35}| 69 | 104 | 173 |---------- | | |
---+-----+-----+-----+-----+ | | | |
5 | 17 | 105 | 122 | 227 | | | | |
---+-----+-----+-----+-----+- Cross 17 Δ26|43Δ30|13Δ17|30
6 | 17 | 123 | 140 | 263 | | | | |
---+-----+-----+-----+-----+ | | | |
7 | 18 | 141 | 159 | 300 |---------- | | |
---+-----+-----+-----+-----+ | | |
8 | 15 | 160 | 175 | 335 |---------------- | |
---+-----+-----+-----+-----+ | |
9 | 15 | 176 | 191 | 367 |---------------------- |
---+-----+-----+-----+-----+ |
10 | 35 | 192 | 227 | 419 |----------------------------
---+-----+-----+-----+-----+Skema ini terjadi dengan adanya crossing angka 17 ke 18 dimana angka 18 merupakan polaritas dari angka id: 2 yang diproses di id: 6 ke angka prima ke-18 yaitu 61.
- 165 - 4 = 161
id: 6
---+-----+-----+-----+-----+
1 | 72 | 1 | 73 | 74 |-----------------
---+-----+-----+-----+-----+ |
2 | 20 | 74 | 94 | 168 |----------- |
---+-----+-----+-----+-----+ | |
3 | 18 | 95 | 113 | 208 |----- | |
---+-----+-----+-----+-----+ | | |
4 | 7 | 114 | 121 | 235 |- {7}| 5 | 1 | {61} = 18th prime
---+-----+-----+-----+-----+ | | |
5 | 13 | 122 | 135 | 257 |----- | |
---+-----+-----+-----+-----+ | |
6 | 19 | 136 | 155 | 291 |----------- |
---+-----+-----+-----+-----+ |
7 | 9 | 156 | 165 | 321 |----------------
---+-----+-----+-----+-----+Hasilnya selisih crossing di id: 26 ini akan mewakili komposisi antara layar dari bilangan² prima. Detilnya anda bisa ikuti pada pembahasan tentang Chart Fungsi Zeta.
- 71 = 1 + 30 + (70 - 30) = 1 + 30 + 40
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{1} |{19}| - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 | 26*| - | 38 | - | - | - | - | - | 74*| - | - | - | 98*| 104*| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27*| - | 39 | - | - | - | - | - | 75*| - | - | - | 99*| 105*| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
5 | 23 |{29}| - | 41 | - | - | - | - | - | 77 | - | - | - {101}| - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
7 | 25 | - | - |{43}| - | 55 | - | - | 73 | 79 | - |{91}| 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - |{57}| - | - | - |{81}| - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
11 | - | - | - | 47 | 53 | 59 | - |{71}| - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - |{61}| 67 | - | - |{85}| - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32*| 50*| - | 62 | 68*| - | - | 86*| - | - | - | - | - | 110*| - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33*|{51*} - | 63 | 69*| - | - | 87*| - | - | - | - | - | 111*| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{18} | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{19} | 2 | {3}| 4 | {5}| 6 | {7}| 8 | {9}| 10 |{11}| 12 |{13}| 14 |{15}| 16 | 17 | 18 |{19}|
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|Perhatikan bahwa angka 29 dan 85 ada di layar-1 dan -3 maka selisih ada di angka 100 ke 300 atau Δ200 sehingga jumlah objek adalah 85 ke 285. Inilah yang mewakili proses 5 ke 7 alur.
Metoda ini adalah cara mengatur jumlah objek 6, 36, dan 72 dimana 6 berlaku sebagai subjek:
- 6 x (1 + 6 + (6 + 6)) = 6 + 36 + 72 = 114
Seperti yang Anda lihat proses ini diawali dari id: 57 yang akan mengambil span 10 objek dimana dia diproses oleh id: 58 via objek yang mewakili angka prima ke-10 yaitu 29 ke 85.
- 29 = 10th prime
id: 57
---+-----+-----
1 | 1 | 15 Δ14
---+-----+-----
2 | 16 | 17 Δ1
---+-----+----- } Δ3
3 | 18 | 20 Δ2
---+-----+----- } Δ 10
4 | 21 |{24} Δ3
---+-----+----- } Δ7
5 |{25} | 29 Δ4
---+-----+-----
15 |Dengan demikian pada formasi id: 58 ini akan terhimpun semua komposisi objek dari Prime-114 dimana pewarisannya akan kita alihkan ke bagan dengan id: 59 via angka 49 ke 94 dan 95 ke 59.
d(19) = d(1+9) = d(10) = d(1+0) = d(1)
layer | node | sub | i | f
------+------+-----+----------
| | | {1} |{2x}
| | 1 +-----+
| 1 | | 2 | 7 (5)
| |-----+-----+
| | | 3 | ..
1 +------+ 2 +-----+----
| | | 4 | 13
| +-----+-----+
| 2 | | 5 | .. (7)
| | 3 +-----+
| | | 6 | 19
------+------+-----+-----+------
| | | {7} | {1x}
| | 4 +-----+
| 3 | | 8 | (11)
| +-----+-----+
| | | 9 |
2 +------| 5 +-----+-----
| | | 10 |
| |-----+-----+
| 4 | | 11 | (13)
| | 6 +-----+
| | | 12 |
------+------+-----+-----+------
| | | {13}| {1x}
| | 7 +-----+
| 5 | | 14 | (17)
| |-----+-----+
| | | 15 |
3 +------+ 8 +-----+-----
| | | 16 |
| |-----+-----+
| 6 | | 17 | (19)
| | 9 +-----+
| | | 18 |
------|------|-----+-----+------
| {19}| ----> 1Penguraian subjek ini kita akan lakukan secara identik dengan metoda mind mapping dimana subjek terbagi enam (6) bagian, setiap bagian terbagi lagi menjadi dua (2) sub² bagian.
Pada 10 baris pertama mewakili prinsip dasar dari projek. Skemanya diambil berdasarkan DOM Object via code html pada halaman dari repository utama yaitu angka satu (1) dan dua (2).
- β(10,13,15,18) = 289 + 95 + 126 + 61 = 285 + 286 = 571
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----
1 | 3 | 1:1:0 | 1 | 2 | {3} | - | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
2 | 4 | 1:2:1 | 4 | 5 | 6 | 7 | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
3 | 6 |*1:2:2 | 8 | 9 | 10 | 11 | 12 | {13}| - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
4 | 6 |*1:3:3 | 14 | 15 | 16 | 17 | 18 | {19}| - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----
10 | 19 |Kesimpulannya adalah bahwa komposisi bilangan² prima ada pada polarisasi hexagon 18 vs 19 dari 114 angka dimana selisih angka 19 ke prima ke-114 yaitu 619 tepat 600.
- 71 = 1 + 30 + (70 - 30) = 1 + 30 + 40
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{1} |{19}| - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 | 26*| - | 38 | - | - | - | - | - | 74*| - | - | - | 98*| 104*| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27*| - | 39 | - | - | - | - | - | 75*| - | - | - | 99*| 105*| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
5 | 23 | 29 | - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
11 | - | - | - | 47 | 53 | 59 | - | 71 | - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32*| 50*| - | 62 | 68*| - | - | 86*| - | - | - | - | - | 110*| - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33*| 51*| - | 63 | 69*| - | - | 87*| - | - | - | - | - | 111*| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
18 | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |{102} - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
19 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 |{15}| 16 | 17 | 18 | 19 |
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|Skema di angka 10 dijalankan dengan id: 57 oleh 29 objek dari Bagan Flowchart. Karena itu ruang lingkup bagan ini dimulai dari angka 30 di layar ke-2 dengan span enampuluh (60).
Angka 60 akan berada tepat di angka dua (2) dimana selisih dari angka prima pertama ini yaitu di angka 2 ke 60 berada tepat di angka 58. Itu sebabnya maka id: 58 menjadi id dari bagan ini.
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+=====
1 | 3 | 1:1:0 | {2} | {60}| {40}| - | - | - | - | - |{102}|
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
2 | 4 | 1:2:1 | ? | ? | ? | ? | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
3 | 6 |*1:2:2 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
4 | 6 |*1:3:3 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+----- | 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{1} |{19}| - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 | 26*| - | 38 | - | - | - | - | - | 74*| - | - | - | 98*| 104*| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27*| - | 39 | - | - | - | - | - | 75*| - | - | - | 99*| 105*| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
5 | 23 | 29 | - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
11 | - | - | - | 47 | 53 | 59 | - | 71 | - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32*| 50*| - | 62 | 68*| - | - | 86*| - | - | - | - | - | 110*| - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33*| 51*| - | 63 | 69*| - | - | 87*| - | - | - | - | - | 111*| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
18 | - |{30}|{36}| - | - | - | - | - | - | - | - | - | - | 102| - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
19 | 2 | {3}|{4} | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --| i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+=====
1 | 3 | 1:1:0 | 2 | 60 | 40 | - | - | - | - | - | 102 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
2 | 4 | 1:2:1 | ? | ? | ? | ? | - | - | - | - | {66}|
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
3 | 6 |*1:2:2 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
4 | 6 |*1:3:3 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+----- i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+=====
1 | 3 | 1:1:0 | 2 | 60 | 40 | - | - | - | - | - | 102 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
2 | 4 | 1:2:1 | {1} | ? | ? | ? | - | - | - | - | 66 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
3 | 6 |*1:2:2 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
4 | 6 |*1:3:3 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+----- i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+=====
1 | 3 | 1:1:0 | 2 | 60 | 40 | - | - | - | - | - | 102 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
2 | 4 | 1:2:1 | 1 | {30}| ? | ? | - | - | - | - | 66 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
3 | 6 |*1:2:2 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
4 | 6 |*1:3:3 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+----- i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+=====
1 | 3 | 1:1:0 | 2 | 60 | 40 | - | - | - | - | - | 102 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
2 | 4 | 1:2:1 | 1 | 30 | {30}| {5} | - | - | - | - | 66 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
3 | 6 |*1:2:2 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
4 | 6 |*1:3:3 | ? | ? | ? | ? | ? | ? | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----Formasi 1 ke 15 mengambil objek 12 ini di angka tiga (3) yang bloknya tujuh (7). Maka akan ada angka yang dipanggil via repdigit 7(111) yang tak lain adalah sang limapuluh tujuh (57).
- 7(111) = 1117 = 7² + 7¹ + 7° = 49 + 7 + 1 = 57
Base
7 | 10
====+====
1 | 1
2 | 2
3 | 3
4 | 4
5 | 5
6 | 6
10 | 7
20 | 14
50 | 35
60 | 42
100 | 48
110 | 56
111 | {57}Disini flowchart ambil wilayah terjauh sampai ke angka 29 sebagai prima ke-10 via objeknya. Dari 13 sd 29 tepat 17. Maka semua titik patok ada limabelas (15) sesuai pola 1 ke 15 dari angka 57:
- 57 x 2 = 114 = 17 + 29 + 68
id: 57
---+-----+-----
1 | 1 | 15 Δ14
---+-----+-----
2 | 16 | 17 Δ1
---+-----+----- } Δ3
3 | 18 | 20 Δ2
---+-----+----- } Δ 10
4 | 21 |{24} Δ3
---+-----+----- } Δ7
5 |{25} | 29 Δ4
---+-----+-----
15 |Detilnya bisa Anda ikuti pada skema expansi hewan ternak di bahasan angka enam (6) tentang alokasi vektor 6x100 dari angka prima ke-114 yaitu 619 kedalam 3 layar via skema 10³ vs 9³:
- Δ prime = 114th prime - 19 = (6 x 19)th prime - 19 = 619 - 19 = 600
Dari formasi bilangan prima ini maka kita dapat menentukan asal muasal angka tujuh (7) yang merupakan pasangan dari angka lima (5) bukan dari 2,3,5 ataupun 7 melainkan 1 dan 6.
Sub | i | β | f
=======+====+=====+======= === === === === === ===
1:1:0 | 1 | 1 | 2 {71} 1 1 | | | |
-------+----+-----+------- --- --- | | | |
1:2:1 | 2 | 2 | 3 {71} | | | | |
-------+----+-----+---- | | | | |
*1:2:2 | 3 | 3 | 7 = 1 + 2x3 | | | | |
-------+----+-----+---- | | | | |
*1:3:3 | 4 | 4 | 10 = 9 + 1 | | | | |
-------+----+-----+---- | | | | |
1:3:4 | 5 | 5 | 11 = 9 + 2 | | | | |
-------+----+-----+---- 9 1‘ | Δ100 |
*1:3:5 | 6 | 6 | 12 = 9 + 3 | | | | |
-------+----+-----+---- | | | | |
*1:4:6 | 7 | 7 | 13 = 9 + 4 | | | | |
-------+----+-----+---- | | | | |
1:4:7 | 8 | 8 | 14 = 9 + 5 | | | | |
-------+----+-----+---- | | | | |
*1:4:8 |{9} | 9 | 15 = 9 + 6 | | | | |
-------+----+-----+---- | | | | |
*1:4:9 |{10}| 10 | 19 = 9 + 10 | | | | |
=======+====+=====+==== === --- 1“ --- |
2:1:0 | 11 | 20 | 20 = 19 + log 10¹ | | | |
-------+----+-----+---- | | | |
2:2:1 | 12 | 30 | 26 = 20 + 2x3 | | | |
-------+----+-----+---- | | | |
*2:2:2 | 13 | 40 | 27 = 26 + 1 | | | |
-------+----+-----+---- | | | |
*2:3:3 | 14 | 50 | 28 = 26 + 2 | | | |
-------+----+-----+---- | | | |
2:3:4 | 15 | 60 | 29 = 26 + 3 9‘ | Δ200 Δ600
-------+----+-----+---- | | | |
*2:3:5 | 16 | 70 | 30 = 26 + 4 | | | |
-------+----+-----+---- | | | |
*2:4:6 | 17 | 80 | 31 = 26 + 5 | | | |
-------+----+-----+---- | | | |
2:4:7 |{18}| 90 | 32 = 26 + 6 | | | |
-------+----+-----+---- | | | |
*2:4:8 |{19}| 100 | 36 = 26 + 10 | | | |
=======+====+=====+==== === --- --- |
*2:4:9 | 20 | 200 | 38 = 36 + log 10² | | |
-------+----+-----+---- | | |
3:1:0 | 21 | 300 | 40 = 36 + 2 x log 10² | | |
-------+----+-----+---- | | |
3:2:1 | 22 | 400 | 41 = 40 + 1 | | |
-------+----+-----+---- | | |
*3:2:2 | 23 | 500 | 42 = 40 + 2 | | |
-------+----+-----+---- | | |
*3:3:3 | 24 | 600 | 43 = 40 + 3 9“ Δ300 |
-------+----+-----+---- | | |
3:3:4 | 25 | 700 | 44 = 40 + 4 | | |
-------+----+-----+---- | | |
*3:3:5 | 26 | 800 | 45 = 40 + 5 | | |
-------+----+-----+---- | | |
*3:4:6 | 27 | 900 | 46 = 40 + 6 | | |
-------+----+-----+---- | | |
3:4:7 |{28}|1000 | 50 = 40 + 10 | | |
=======+====+=====+==== === ==== ----
*3:4:8 |{29}|2000 | 68 = 50 + 3 x (2x3) {10³} Δ600 Δ300
=======+====+=====+==== Δ ====
3:4:9 |{30}|3000 |{71}= 68 + log 10³ ---------¤ Δ900 Penerapan siklus tigapuluh (30) terhadap konfigurasi sembilan (9) dari formasi {3,6,9} dimana dari kedua angka ini akan membentuk formasi Δ900 ke Δ600 yaitu 300 + 900/100 atau 309.
Untuk menjelaskan siklus tiga (3) layar ini sekarang saya ajak Anda kita kembali ke Tabulasi Prime Hexagon. Perhatikan angka² ditandai merah.
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
1 | 19 | - |{31}| 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 |{26}| - | 38 | - | - | - | - | - | 74 | - | - | - | 98 | 104 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27 | - | 39 | - | - | - | - | - | 75 | - | - | - | 99 | 105 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
5 | 23 | 29 | - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
11 | - | - | - | 47 | 53 | 59 | - |{71}| - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - |{61}| 67 | - | - | 85 | - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32 | 50 | - | 62 | 68 | - | - | 86 | - | - | - | - | - | 110 | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33 | 51 | - | 63 | 69 | - | - | 87 | - | - | - | - | - | 111 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
18 | - |{30}| 36 | - | - | - | - | - | - | - | - | - | - |102 | - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
1 | 2 | 3 | {4}| 5 | 6 | {7}| 8 | {9}| 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|Elemen dari 309 ini terdiri dari Δ300 dan Δ9 akan berlaku sebagai input pada proses berikutnya terhadap angka 10 dan 9 yaitu ke 300/10 dan 9/9 tepatnya di angka 30 ke 31.
Berdasarkan uraian tentang perpindahan layar yang diakibatkan oleh perubahan arah polaritas dari minor hexagon maka nilai vektor di tiap layar kita tambahkan Δ100.
layer | node | sub | i | f
------+------+-----+----------
| | | 1 | 2x -----¤ (2,{60,40})
| | 1 +-----+ |
| 1 | | 2 | 7 (5)
| |-----+-----+ |
| | | 3 |{3x} ----¤ <--- 3x100
1 +------+ 2 +-----+---- |
| | | 4 | 13 |
| +-----+-----+ |
| 2 | | 5 |{2x}-----¤ <--- 2x100
| | 3 +-----+
| | | 6 | 19
------+------+-----+-----+------
| | | 7 | 1x
| | 4 +-----+
| 3 | | 8 | (11)
| +-----+-----+
| | | 9 |
2 +------| 5 +-----+-----
| | | 10 |
| |-----+-----+
| 4 | | 11 | (13)
| | 6 +-----+
| | | 12 |
------+------+-----+-----+------
| | | 13 | 1x
| | 7 +-----+
| 5 | | 14 | (17)
| |-----+-----+
| | | 15 |
3 +------+ 8 +-----+-----
| | | 16 |
| |-----+-----+
| 6 | | 17 | (19)
| | 9 +-----+
| | | 18 |
------|------|-----+-----+------ i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+=====
1 | 3 | 1:1:0 | 2 | 60 | 40 | - | - | - | - | - | 102 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
2 | 4 | 1:2:1 | 1 | 30 | 30 | 5 | - | - | - | - | 66 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
3 | 6 |*1:2:2 | {1} | {30}| ? | ? | ? | ? | - | - |{329}|
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
4 | 6 |*1:3:3 | {1} | {30}| ? | ? | ? | ? | - | - |{289}|
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+----- | 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
1 | 19 | - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 | 26*| - | 38 | - | - | - | - | - | 74*| - | - | - | 98*| 104*| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27*| - | 39 | - | - | - | - | - | 75*| - | - | - | 99*| 105*| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{5} | 23 |{29}| - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{11} | - | - | - | 47 | 53 | 59 | - | 71 | - | 83 |{89}| 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32*| 50*| - | 62 | 68*| - | - | 86*| - | - | - | - | - | 110*| - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33*| 51*| - | 63 | 69*| - | - | 87*| - | - | - | - | - | 111*| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
18 | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - | 102| - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
19 | 2 | {3}| 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 |{12}| 13 | 14 | 15 | 16 | 17 | 18 | 19 |
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|layer | node | sub | i | f
------+------+-----+----------
| | | 1 | 2x ----¤ (2,60,{40})
| | 1 +-----+ |
| 1 | | 2 | 7 {5x}
| |-----+-----+ |
| | | 3 |{3x} ----¤ <--- 11
1 +------+ 2 +-----+---- |
| | | 4 | 13 |
| +-----+-----+ |
| 2 | | 5 |{2x}-----¤ <--- 17
| | 3 +-----+
| | | 6 | 19
------+------+-----+-----+------
| | | 7 | 1x
| | 4 +-----+
| 3 | | 8 | (11)
| +-----+-----+
| | | 9 |
2 +------| 5 +-----+-----
| | | 10 |
| |-----+-----+
| 4 | | 11 | (13)
| | 6 +-----+
| | | 12 |
------+------+-----+-----+------
| | | 13 | 1x
| | 7 +-----+
| 5 | | 14 | (17)
| |-----+-----+
| | | 15 |
3 +------+ 8 +-----+-----
| | | 16 |
| |-----+-----+
| 6 | | 17 | (19)
| | 9 +-----+
| | | 18 |
------|------|-----+-----+------ i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+=====
1 | 3 | 1:1:0 | 2 | 60 | 40 | - | - | - | - | - | 102 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
2 | 4 | 1:2:1 | 1 | 30 | 30 | 5 | - | - | - | - | 66 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
3 | 6 |*1:2:2 | 1 | 30 |{200}| {8} | ? | ? | - | - |{329}|
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
4 | 6 |*1:3:3 | 1 | 30 |{200}| {8} | ? | ? | - | - |{289}|
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----layer | node | sub | i | f
------+------+-----+----------
| | | 1 | 2x -----¤ (2,60,40)
| | 1 +-----+ |
| 1 | | 2 | 7 {5x}
| |-----+-----+ |
| | | 3 | 3x ----¤ <--- 11
1 +------+ 2 +-----+---- |
| | | 4 | 13 |
| +-----+-----+ |
| 2 | | 5 |{2x} ----¤ <--- 17²=289
| | 3 +-----+
| | | 6 | 19
------+------+-----+-----+------
| | | 7 | 1x
| | 4 +-----+
| 3 | | 8 | (11)
| +-----+-----+
| | | 9 |
2 +------| 5 +-----+-----
| | | 10 |
| |-----+-----+
| 4 | | 11 | (13)
| | 6 +-----+
| | | 12 |
------+------+-----+-----+------
| | | 13 | 1x
| | 7 +-----+
| 5 | | 14 | (17)
| |-----+-----+
| | | 15 |
3 +------+ 8 +-----+-----
| | | 16 |
| |-----+-----+
| 6 | | 17 | (19)
| | 9 +-----+
| | | 18 |
------|------|-----+-----+------Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----
1 | 3 | 1:1:0 | 2 | 60 | {40}| - | - | - | - | - | 102 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
2 | 4 | 1:2:1 | 1 | 30 | 30 | 5 | - | - | - | - | 66 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ {786}
3 | 6 |*1:2:2 | 1 | 30 | 200 | 8 | {40}| {50}| - | - | 329 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
4 | 6 |*1:3:3 | 1 | 30 | 200 | 8 | {10}| {40}| - | - | 289 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----Hasil mulanya kedua akun akan menuju formasi 786 ke dobel helix yang digerakkan vektor 71 dan 68 berdasarkan susunan angka prima pada kubus 10x10x10 atau 1000 terhadap Golden Ratio.
- π(1000) + 1000/Φ = 168 + 618 = (7x71) + (17x17) = 786
Selanjutnya kita akan bahas bagaimana formasi angka² ini pada setiap layar. Seperti yang sudah dijelaskan sebelumnya semua ada tiga (3) layar. Kita mulai dari formasi 786 di layar-1.
Pada pembagian di layar-1 ini angka 29 akan berkorelasi dengan polar 12 ke 18 sehingga angka yang berperan adalah delapan belas (18) maka pada prosesnya dilakukan via 18 x id: 79 ke 96.
- d(43,71,114) = d(7,8,6) » 786
Berikut ini detil formasi 786 berbasis batas polaritas di angka 19 pada layar-1 yang terbagi dalam 3 kelompok dengan formasi (7,13,19). Persis seperti halnya skema True Prime Pairs.
- π(1000) = π(Φ x 618) = 168 = 100 + 68 = (50x2) + (66+2) = 102 + 66
$True Prime Pairs:
(5,7), (11,13), (17,19)
layer| i | f
-----+-----+---------
| 1 | 5
1 +-----+
| 2 | 7
-----+-----+--- } 36 » 6®
| 3 | 11
2 +-----+
| 4 | 13
-----+-----+---------
| 5 | 17
3 +-----+ } 36 » 6®
| 6 | 19
-----+-----+---------
Scheme:
168 + 329 + 289 = 786
d(786) = d(7+8+6) = d(21) = d(3)
Modulus:
30 « 60 » 90
| | |
3:29 « 1:6:8 » 28:9
└── 3 + └── 6 + └── 9 = 18
|------------ 36' --------------|----------------------------36' ----------------------------|
| 19' | 17' | 13' | 11' | 7' | 5' |
+---+----+----+---+----+----+---+---+----+-----+----+----+----+----+----+-----+----+----+----+
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
+---+----+----+---+----+----+---+---+----+-----+----+----+----+----+----+-----+----+----+----+
| 2 | 60 | 40 | 1 | 30 | 30 | 5 | 1 | 30 | 200 | 8 | 40 | 50 | 1 | 30 | 200 | 8 | 10 | 40 |
+---+----+----+---+----+----+---+---+----+-----+----+----+----+----+----+-----+----+----+----+
| ° |ΔΔΔΔ ΦΦ | • ΔΔ ΔΔ ¤ | • ΔΔ ΦΦΦ Φ ΦΦ ¤¤¤¤| • ΔΔ ΦΦΦ Φ ¤¤ ΦΦ |
|---- 102 ---|----- 66 ------|-------- 329 = 7 x 47 -------|- 289 = (8+9)² = 2 & (2³+9²) -|
|--2x3x(8+9)--|--- 2x3x(2+9) ---|---- (1+2) & (2x9)+(2+9) ----|------ 2 & (8x9)+(8+9) -------|
|-------- 168 = π(1000) --------|------ 1229 = π(10000) ------|------ π(89²) = 1000 ---------|
|-------- 168 = π(618xΦ) -------|----- 618 = 1000/Φ = 1000x1000/1618 = 10^6/(2x8)&(2x9) -----|
Note:
• = 1000 = 10³ (Triple Ten)
¤ = π(1000) = 168 (Basic Primes)
Φ = 1000/618 = 1,618 (Golden Ratio)
Δ(1,6,18) = 61+28 = 89 (Mersenne Primes)
Faktors:
168 = 12x14 = 8x21 = 7x24 = 6x28 = 4x42 = 3x56 = 2x84
618 = 6x103 = 6x(100+3) = 3x206 = 3x(200+6) = 2x309 = 2x(300+9)
1+6+8 = π(1x6x8) = π(1x48) = π(2x24) = π(3x16)= π(4x12) = π(6x8)
Permutations:
168 = 102 + 66 = 2x3x((8+9)+(2+9)) = π(Φ(289+329)) = π(Φ((8+9)²+(1+2)&29))
168 + 618 = 168 + 329 + 289 = (7x24) + (7x47) + (8+9)² = (7x71) + (17x17)Pola seperti ini dilakukan secara mirror 17 via 29 urutan formasi (1,2,3) dari True Prime Pairs pada batas (7,13,19) dengan komposisi repository 2®+5®+6®+6® ke 43+48+48 atau 43+96.
Berikutnya kita bahas formasi bobot di layar-2.
Dari 19 angka yang kita sudah dapatkan dari skema (7,13,19) ini kita akan rubah ke format (3,6,9) sehingga urutannya menjadi (3,4,3,3,6) yang akan kita proses ke formasi berikutnya.
layer | node | sub | i | f
------+------+-----+----------
| | | 1 | 2x
| | 1 +-----+
| 1 | | 2 | 7
| |-----+-----+
| | | 3 | 3x ----
1 +------+ 2 +-----+---- |
| | | 4 | 13 5x ----
| +-----+-----+ | |
| 2 | | 5 | 2x ---- (7)
| | 3 +-----+ |
| | | 6 | 19 |
------+------+-----+-----+------ |
| | | 7 | 1x |
| | 4 +-----+ |
| 3 | | 8 | 1x ---- | (11)
| +-----+-----+ | |
| | | 9 | .. {2x}----
2 +------| 5 +-----+----- |
| | | 10 | 1x ----
| |-----+-----+
| 4 | | 11 | (13)
| | 6 +-----+
| | | 12 |
------+------+-----+-----+------
| | | 13 | 1x
| | 7 +-----+
| 5 | | 14 | (17)
| |-----+-----+
| | | 15 |
3 +------+ 8 +-----+-----
| | | 16 |
| |-----+-----+
| 6 | | 17 | (19)
| | 9 +-----+
| | | 18 |
------|------|-----+-----+------Dengan rotasi angka 12 pada setiap angka dari (3,4,3,3,6) akan muncul formasi (4,3,4,4,2) dimana palindromnya adalah (2,4,4,3,4) yang berkolerasi dengan 286 objek dari angka dua (2).
- 24434 / 19 = 1286
id: 6
123 247
Δ Δ
---+-----+-----+-----+-----+
1 | 72 | 1 | 73 | {74}|-----------------
---+-----+-----+-----+-----+ |
2 | 20 | 74 |{94} | 168 |----------- |
---+-----+-----+-----+-----+ | |
3 | 18 |{95} | 113 | 208 |----- | |
---+-----+-----+-----+-----+ | | |
4 | {7}| 114 | 121 | 235 |- {7}| 5 | 1 | {61} = 18th prime
---+-----+-----+-----+-----+ | | |
5 | {13}| 122 | 135 | 257 |----- | |
---+-----+-----+-----+-----+ | |
6 | {19}| 136 | 155 | 291 |----------- |
---+-----+-----+-----+-----+ |
7 | {9}| 156 | 165 | 321 |----------------
---+-----+-----+-----+-----+
Δ Δ
139 286 Pola ini ada di Chart Fungsi Zeta via 3x6 dari 18 polarisas angka dua (2) versus 19 putaran tiga (3) hexagon dari 18 ke 19 yabg bertumpu di 5 vs 6 titik dengan Δ polar tepat 2x(7,10) ke 14 dan 20.
- 20 x 10 = 200 = 16 x 6 + (10² + 14 - 10) = 96 + 114 - 10 = 96 + 104
Palindrome antara (6,3,3,4,3) ke (2,4,4,3,4) ini adalah transformasi dari angka 19 ke 17 merupakan palindrome dari angka 71 maka disini kita dapatkan formasi dari Skema in-out.
- 71 = 1 + 30 + (70 - 30) = 1 + 30 + 40
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{1} |{19}| - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 | 26*| - | 38 | - | - | - | - | - | 74*| - | - | - | 98*| 104*| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27*| - | 39 | - | - | - | - | - | 75*| - | - | - | 99*| 105*| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
5 | 23 | 29 | - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
11 | - | - | - | 47 | 53 | 59 | - |{71}| - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32*| 50*| - | 62 | 68*| - | - | 86*| - | - | - | - | - | 110*| - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33*| 51*| - | 63 | 69*| - | - | 87*| - | - | - | - | - | 111*| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
18 | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
19 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | {17}| 18 | 19 |
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|Dari format ini kita akan sampai ke formasi 6 ke 2 via 17 ke 20. Jadi skema ini hanya bisa kita dapatkan dengan format angka (18,19,20) yang terdapat pada Chart Fungsi Zeta.
Seluruh proses P(7):142857 sampai ke vektor di angka 31 ke 231 yang diuraikan di atas berada dalam lingkup flowchart yang dialokasikan dengan id: 57.
- 1155 / 5 = 286 - 55 = 200 + 31 = 231
layer| i | f
-----+-------+------
| 1,2:1 | (2,3)
1 +-------+
| 3:2 | (7)
-----+-------+------
| 4,6:3 | (10,11,12) <--- 231 (3x)
2 +-------+
|{7}:4 |({13})
-----+-------+------
| 8,9:5 | (14,{15}) <--- 231 (2x)
3 +-------+
| 10:6 | (19)
-----+-------+------- 286 - (231x5)/(11x7) = 286 - 1155/77 = 286 - 15 = 200 + 71 = 271
- 114 - 19 = 19 x 5 = 95 = d(14)
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
1 |{19}| - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 |{20}| 26 | - | 38 | - | - | - | - | - | 74 | - | - | - | 98 | 104 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27 | - | 39 | - | - | - | - | - | 75 | - | - | - | 99 | 105 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
5 | 23 | 29 | - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
11 | - | - | - | 47 | 53 | 59 | - | 71 | - | 83 | 89 |{95}| - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{14} | - | - | 32 | 50 | - | 62 | 68 | - | - | 86 | - | - | - | - | - | 110 | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33 | 51 | - | 63 | 69 | - | - | 87 | - | - | - | - | - | 111 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
18 | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{19} | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 |{12}|{13}| 14 | 15 | 16 | 17 | 18 | 19 |
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|layer| i | f
-----+-------+------
| 1,2:1 | (2,3)
+-------+
| 3:2 | (7)
+-------+------
| 4,6:3 | (10,11,12)
1 +-------+
| 7:4 | (13)
+-------+------
| 8,9:5 | (14,15)
+-------+
| 10:6 | (19) <--- 195
-----+-------+------
| 7 | 1x ({20})
+-------+
2 | 8 |
+-------+
| 13:9 | 1x
-----+-------+------
| 10 |
+-------+
3 | 11 |
+-------+
| 19:12 | 1x
-----+-------+------
Permutation:
each index of 7,13,19 has only one faktor
- 73 » 7 x 3 = 21 = d(3)
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
1 |{19}| - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 |{20}| 26 | - | 38 | - | - | - | - | - | 74 | - | - | - | 98 | 104 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 |{21}| 27 | - | 39 | - | - | - | - | - | 75 | - | - | - | 99 | 105 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 |{22}| 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
5 |{23}| 29 | - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 |{24}| - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{7} |{25}| - | - | 43 | - | 55 | - | - |{73}| 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
11 | - | - | - | 47 | 53 | 59 | - | 71 | - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32 | 50 | - | 62 | 68 | - | - | 86 | - | - | - | - | - | 110 | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33 | 51 | - | 63 | 69 | - | - | 87 | - | - | - | - | - | 111 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
18 | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{1} | {2}| 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|-- 121 --|Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
5 | 5 | 1:3:4 | 1 | 30 | ? | ? | ? | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
6 | 3 |*1:3:5 | ? | ? | ? | - | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
7 | 2 |*1:4:6 | ? | ? | - | - | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
8 | 7 | 1:4:7 | ? | ? | ? | ? | ? | ? | ? | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
5 | 5 | 1:3:4 | 1 | 30 | 8 | 40 | 4 | - | - | - | 83 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
6 | 3 |*1:3:5 | ? | ? | ? | - | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ {581}
7 | 2 |*1:4:6 | ? | ? | - | - | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
8 | 7 | 1:4:7 | ? | ? | ? | ? | ? | ? | ? | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----layer| i | f
-----+-------+------
| 1,2:1 | (2x3) ----------2x--
+-------+ |
| 3:2 | (7) |
+-------+------ |
| 4,6:3 | (10,11,12) --- |
1 +-------+ | |
| 7:4 | (13) | 5x |
+-------+------ | |
| 8,9:5 | (14,15) ------ |
+-------+ |
| 10:6 | (19) |
-----+-------+------ | 6x √
| 11:7 | (20) |
+-------+ |
2 | 12:8 | (26) --------- |
+-------+ | |
| 13:9 | (27) <-- 69 | 2x |
-----+-------+------ | |
| 14:10 | ({28}) ------- |
+-------+ |
3 | 11 | (29,30,31,32) --4x--
+-------+
| 19:12 | (36)
-----+-------+------
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
1 | 19 | - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 | 26 | - | 38 | - | - | - | - | - | 74 | - | - | - | 98 | 104 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27 | - | 39 | - | - | - | - | - | 75 | - | - | - | 99 | 105 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 |{28}| - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
5 | 23 | 29 | - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
11 | - | - | - | 47 | 53 | 59 | - | 71 | - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - |{109}| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32 | 50 | - | 62 | 68 | - | - | 86 | - | - | - | - | - | 110 | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33 | 51 | - | 63 | 69 | - | - | 87 | - | - | - | - | - | 111 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
18 | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
5 | 5 | 1:3:4 | 1 | 30 | 8 | 40 | 4 | - | - | - | 83 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
6 | 3 |*1:3:5 | 30 | 30 | 5 | - | - | - | - | - | 65 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ {581}
7 | 2 |*1:4:6 | ? | ? | - | - | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
8 | 7 | 1:4:7 | ? | ? | ? | ? | ? | ? | ? | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----layer| i | f
-----+-------+------
| 1,2:1 | (2x3) ----------2x--
+-------+ |
| 3:2 | (7) |
+-------+------ |
| 4,6:3 | (10,11,12) --- |
1 +-------+ | |
| 7:4 | (13) | 5x |
+-------+------ | |
| 8,9:5 | (14,15) ------ |
+-------+ |
| 10:6 | (19) |
-----+-------+------ | 6x √
| 11:7 | (20) |
+-------+ |
2 | 12:8 | (26) --------- |
+-------+ | |
| 13:9 | (27) <-- 69 | 2x |
-----+-------+------ | |
| 14:10 | (28) --------- |
+-------+ |
3 | 11 | ({29,30,31,32}) -4x-
+-------+
| 19:12 | (36)
-----+-------+------
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
1 | 19 | - |{31}| 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 | 26 | - | 38 | - | - | - | - | - | 74 | - | - | - | 98 | 104 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27 | - | 39 | - | - | - | - | - | 75 | - | - | - | 99 | 105 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
5 | 23 |{29}| - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - |{70}| - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
11 | - | - | - | 47 | 53 | 59 | - |{71}| - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - |{32}| 50 | - | 62 | 68 | - | - | 86 | - | - | - | - | - | 110 | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33 | 51 | - | 63 | 69 | - | - | 87 | - | - | - | - | - | 111 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
18 | - |{30}|{36}| - | - | - | - | - | - | - | - | - | - |102 | - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
5 | 5 | 1:3:4 | 1 | 30 | 8 | 40 | 4 | - | - | - | 83 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
6 | 3 |*1:3:5 | 30 | 30 | 5 | - | - | - | - | - | 65 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ {581}
7 | 2 |*1:4:6 | 200 | 2 | - | - | - | - | - | - | 202 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
8 | 7 | 1:4:7 | ? | ? | ? | ? | ? | ? | ? | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----Format ini menggenapkan trasformasi 19 ke 17 yang diuraikan sebelumnya pada angka 9 dan 10 sekaligus menempatkan formasi 12 untuk mewakili angka 1 dan 2 ke Skema 111+3.
id: 12
---+-----+-----
1 | {1} | {2}
---+-----+-----
2 | 3 | 101
---+-----+-----
3 |{102}| 111
---+-----+-----Filosofi dari Skema 111+3 ini tak lain adalah formasi dari angka 114 dari pasangan angka prima 11 dan 13 berlaku sebagai basis 17 ke 29 via selisih dari keduanya yaitu angka 12 tadi:
id: 18
---+-----+-----
1 | 1 | 5 ----
---+-----+----- |
2 | 6 | 8 |
---+-----+----- | 2nd
3 | 9 |{26} |
---+-----+----- |
4 |{27} | 28 --3-¤
---+-----+----- | 3rd
5 | 29 | 31 ----
---+-----+-----
6 | 32 | 32 ----
---+-----+----- |
7 | 33 | 44 |
---+-----+----- | 4th
8 | 45 | 46 |
---+-----+----- |
9 | 47 |{49} --6-¤
---+-----+----- | 5th
10 |{50} | 50 ----
---+-----+-----
11 | 51 | 53 ----
---+-----+----- |
12 | 54 | 59 |
---+-----+----- | 6th
13 | 60 | 82 |
---+-----+----- |
14 | 83 |{102} --9-¤
---+-----+----- | 7th
15 |{103}| 110 ----
---+-----+-----Yang akan berperan dalam proses 12 ke 18 ini adalah angka seratus dua (102). Seperti yang kita sudah bahas dia ada di ujung dari Prime Hexagon dalam format (2,60,40).
id:58
---+-----+-----+
1 | 1 | {4} | 4¤
---+-----+-----+ } 13¤
2 | {5} | 13 | 9¤ } 31¤
---+-----+-----+ } 18¤
3 | 14 |{22} | 9¤
---+-----+-----+Berikut adalah konfigurasi bagaimana skema 17 ke 29 dijalankan. Disini Anda bisa melihat posisi angka duabelas (12) berdasarkan peran 22 objek dari id: 58 yang sedang kita bahas:
- 12 + (15 + 19) + 22 = (12 + 34) + 22 = 46 + 22 = 68
Chetabahana Project
1: Site Φ(11-13) ----------
2: Main |
3: Project ----------------¤ {5}
4: Pratinjau |
5: Pola Dasar -------------¤ Φ(11-13)
6: Bagan Kerja |
7: Field Tutorial |
8: Cloud Site API |
9: Google Ads API ---------¤ {7}
10: Cloud Tasks API |
11: Google Trends API |
12: Basis Implementasi ----
Daftar Isi
13: Beranda (13-18) ------------
14: Dunia Internet |
18: Situs Online (18,31) ---¤ Φ(1-31)
19: Project Online |
20: Apa itu GitHub |
15: Programming ----------------¤ {11}
21: Cara Daftar |
30: Personal |
31: Organisasi ---------
22: Implementasi <-------- 58=Φ(32-33)
32: GitHub API (32-36)--
33: Fitur GitHub |
23: Kenapa GitHub |
34: GitHub Actions |
35: Metoda GitHub |
16: Publishing |
24: Program |
36: Skema (36-50) -----¤ Φ(32-50)
37: API v3 |
38: API v4 |
25: Optimasi |
39: Plugin |
40: Redirect |
41: Sub Modul |
42: Situs GitHub |
43: Jekyll/Liquid |
26: Collections ------------¤ {13}
44: Size |
45: Form |
46: Hooks |
47: Big Size |
48: Interface |
49: Branching |
50: Application --------
{17}: Package
27: Bagan (1-31) ---------------
51: Attribute (1-5) |
52: Artifacts (6-8) |
53: Method (9-26) ----------¤ 1-31 Δ(30,31)
54: Model (27-28) |
55: Trace (29-31) |
56: Track (31-32) ----------
{28}:Diagram (32-50) ------------
57: Flowchart (32-32) |
58: Sequence (32-33) |
59: Grammar (33-44) --------¤ 32-50 Δ(18,19)
60: Channel (45-46) |
61: Route (47-49) |
62: Tree (49-50) ---------
{29}:Mapping (50-110) -----------
63: Sizing (50-51) |
64: Sorting (51-53) |
65: Listener (54-59) -------¤ 50-110 Δ(60,61)
66: Looping (60-82) |
67: Capturing (83-102) |
{68}:Directions (103-110) ---¤->(111-113)->Φ(11,13)- 12 + (15 + 19) + 22 = (12 + 34) + 22 = 46 + 22 = 68
Dengan demikian ruang lingkup dari Bagan Sequence ini adalah sebagai koneksi 32 ke 33 dengan kata lain menguraikan 5 ke 8 dimana proses selanjutnya kita alihkan ke 58 plus 1 atau id: 59.
Pola pada angka sembilanpuluh enam (96) ini adalah berupa 19 tahapan terdiri dari gabungan proses (4+1) dengan paket berikutnya yaitu 14 tahapan menuju sistem 114:
- 6 x 19 = 6 x (1 & 9) = 6 x (1 & (4,5)) = π(6 & (14+5)) = π(6 & 19) = π(619) = 114
id: 96
i | q | r | o | primes
===+=====+====+====+=====+=====
1 | 1 | 5 |{20}| 76 | 76
---+-----+----+----+-----+-----
2 | 6 | 8 |{11}| 11 | 87
---+-----+----+----+-----+-----
3 | 9 | 14 |{23}| 116 | 203
---+-----+----+----+-----+-----
4 | 15 |{18}| 13 | {62}| 265
---+-----+----+----+-----+-----
5 |{19} | 19 | 5 | 20 |{285}
===+=====+====+====+=====+=====
15 | 50 | 64 | 72 | 285 | 285
Permutations:
5 = 1 + 4
15 = 9 + 6
19 = 5 + 14
72 = 4 x 18
114 = 72 + 42
285 = 15 x 19
47 = 15th primeYang khusus darinya adalah bahwasanya struktur tiap unit DNA di tubuh kita ini dibangun dari kedua angka ini. Mereka membentuk format 2 vs 3 ikatan hidrogen.
Seperti Anda lihat pada gambar pasangan unit DNA ini terbentuk bersilangan yaitu 6 ke 9 dan 9 ke 6 dimana perbandingan angka nya sesuai ikatan hidrogen yaitu 2 vs 3.
Jumlah 9 dan 6 adalah 15. Pada tabulasi dibawah ini indek dan nilainya ada di 15 dan 23 dimana angka ini adalah gabungan 2 vs 3 yang terkonversi kedalam format (10,29) dan (32,68).
layer | node | sub | i | k | f
------+------+-----+-----+-----+-----
| | | 1 | 1,2 | {71}=68+3 (2,3) -- 2x --
| | 1 +-----+-----+ |
| 1 | | 2 | 3 | 161 (7) |
| |-----+-----+-----+ |
| | | 3 | 4,6 | 10,11,12 -- |
1 +------+ 2 +-----+-----+ | |
| | | 4 | 7 | 13 5x --- |
| +-----+-----+-----+ | | |
| 2 | | 5 | 8,9 | 14,15 ----- | |
| | 3 +-----+-----+ | |
| | | 6 | 10 | 19 | |
------+------+-----+-----+-----+-------- 7x + {6x} = 13x
| | | 7 | 11 | 20 | |
| | 4 +-----+-----+ | |
| 3 | | 8 | 12 | 26 ----- | |
| +-----+-----+-----+ | | |
| | | 9 | 13 | 27 2x ----- |
2 +------| 5 +-----+-----+ | |
| | | 10 | 14 | 28 ----- |
| |-----+-----+-----+ |
| 4 | | 11 |15,18| 29,30,31,32 <----4x----
| | 6 +-----+-----+
| | | 12 | 19 | 36
------+------+-----+-----+-----+-------
| | | 13 | 20 | 38
| | 7 +-----+-----+
| 5 | | 14 |21,22| 40,41 = (19-17)x ------
| |-----+-----+-----+ |
| | | 15 | 23 | 42 {6x} + 13x = 19x
3 +------+ 8 +-----+-----+ |
| | | 16 |24,27| 43,44,45,46 <-- 4x ---
| |-----+-----+-----+
| 6 | | 17 | 28 | 50 = 46 + 4
| | 9 +-----+-----+
| | | 18 | 29 | 68
------|------|-----+-----+------Disini kita satukan dengan seluruh ikatan yang tentunya adalah jumlah keduanya yaitu 100 maka jumlah dari basis DNA yaitu Pospat, Gula dan Nukeotida adalah 200 dengan format (70,30,100).
#8 |--------- 6® ----------|---------- 6® ------------|
| 1 |-------------- 77 = 4² + 5² + 6² -------------|
------+---|---+---+---+---+---+---+---+---+----+----+----+
repo |{1}|{2}| 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 |{12}| ∑ 1,{77}
------+---|---+---+---+---+---+---+---+---+----+----+----+
user | 7 | - | - | - | - | 7 | 8 | - | - | 8 | 8 | 3 | (1,2,3)
------+---|---+---+---+---+---+---+---+---+----+----+----+--------- ∑ 7,{78}
main | - | 9 | 7 | 9 | 6 | - | - | 8 | 5 | - | - | - | (4,2)
------+---|---+---+---+---+---+---+---+---+----+----+----+
Δ | Δ | Δ | Δ
Φ17|Φ29 | 96-99| 100-123 ({24})
|--- A,T,G,C ---| | └── 100 - 103 (4x) » 100
Δ 2x2 = 4x |------- 2x3 = 6x -------| └── 104 - 109 (6x) » 30
{98} | └── 110 - 123 (14x)» 70Basis DNA ini tentu tidak terjadi dengan sendirinya. Keberadaannya so pasti berasalkan dari suatu proses tertentu pada partikel² dari elemen yang ada di muka bumi ini.
- π(96) = 96/4 = 24
Sekarang kita coba hitung bagaimana urusannya suatu partikel bisa naik menjadi bagian dari Unit DNA pada setiap spesies tunggal termasuk manusia sehingga bisa ada hidup di dunia ini.
Sesuai uraian tentang Format (70,30,100) yang merupakan awal mula Unit DNA ini diperoleh id: 58 berdasarkan hasil dari proses yang bisa Anda ikuti detil ceritanya di id: 32 dan 33.
Singkatnya ini berhubungan dengan Skema 111+3 yaitu Sistem Tata Surya dimana sistem orbital planet akan kita jumpai pada konfigurasi elektron dari Struktur Atom.
Sistem DNA terdiri dari unit atom². Dalam mekanika kuantum, bilangan kuantum diperlukan untuk menggambarkan distribusi elektron dalam atom hidrogen dan atom-atom lain.
- Terdapat seperangkat bilangan kuantum yang terkait dengan keadaan energi atom. Empat bilangan kuantum n, ℓ, m, dan s menentukan keadaan kuantum elektron tunggal yang unik dan lengkap dalam sebuah atom, yang disebut fungsi gelombang atau orbital.
- Dua elektron dalam atom yang sama tidak dapat memiliki empat bilangan kuantum yang sama, sesuai prinsip pengecualian Pauli.
Konfigurasi ini akan selalu memunculkan angka empat (4) sebagai batas akhir baik digambarkan berupa lingkaran maupun tingkatan energi. Ini yang jarang diulas secara detil.
Sekarang tempatkan diri Anda sebagai partikel elektron yang harus melewati formasi 12 angka untuk menjadi DNA dimana setiap Anda berputar identik dengan putaran bumi yaitu 1 hari.
Maka urusan di angka 30 dalam 1 hari adalah orbital bulan dalam satu tahun dimana P(7):142857 harus berotasi tepat 12 terhadap 1000 bulan ke 12000 hingga rasionya ada di kecepatan cahaya.
Dengan demikian berdasarkan Skema in-out bisa dipastikan bahwa alam semesta ini adalah input bagi alam lain lagi yang tak mungkin bisa kita bayangkan. Jadi ini sudah diluar lingkup bahasan.
Jadi angka empat (4) ini sebenarnya adalah peran id: 32 persis angka ke-2 dari Pola P(7):142557 pada formasi 10 dan 9 terhadap angka 309 yang diproses id: 30 ke 31 via 300/10 dan 9/9.
id: 32
---+-----+-----
1 | 1 | 6
---+-----+-----
2 | 7 | 14
---+-----+-----
3 | 15 |{22}
---+-----+-----
4 |{23} | 27
---+-----+-----
5 | 28 |{30}
---+-----+-----Peran angka tigapuluh tiga (33) adalah transformasi via akar digital dari angka 13 ke 40 terhadap 43 objek yang dimilikinya sehingga polarisasi 71 pada Skema 111+3 ada dalam format 72 ke 73.
- 13 + 43 = d(13) + d(43) = d(40 + 43) = d(73)
id: 33
---+-----+-----
1 | 1 | 3
---+-----+-----
2 | 4 | 6
---+-----+-----
3 | 7 | 8
---+-----+-----
4 | 9 | 21
---+-----+-----
5 |{22} |{25}
---+-----+-----
6 | 26 | 27
---+-----+-----
7 |{28} |{40}
---+-----+-----
8 |{41} | 48
---+-----+-----
9 | 49 | 59
---+-----+-----
10 |{60} |{68}
---+-----+-----
11 | 69 | 71
---+-----+-----
12 | 72 | 73
---+-----+-----Skema 111+3 ini kita proses berdasarkan alokasi tujuh (7) id yaitu (10,11,12), (14,15) dan (26,28) ke Tujuh (7) Kasus Milenial untuk dibawa oleh id: 29 via id (30,31) dan (32,33) ke id: 58.
Dengan kata lain ilmu yang menyangkut urusan dari pembentukan Unit DNA ini sedikitnya adalah solusi dari Tujuh (7) Kasus Milenial yang sampai saat ini baru satu (1) yang sudah ditemukan.
Selanjutnya kita bahas translasi yang dijalankan oleh Bagan Sequence dari formasi 10 ke 29 pada Skema P(7):142857 yang dikonversikan ke angka enam (6) via korelasi dari angka 12 ke 18.
id: 6
123 247
Δ Δ
---+-----+-----+-----+-----+
1 | 72 | 1 | 73 | {74}|-----------------
---+-----+-----+-----+-----+ |
2 | 20 | 74 |{94} | 168 |----------- |
---+-----+-----+-----+-----+ | |
3 | 18 |{95} | 113 | 208 |----- | |
---+-----+-----+-----+-----+ | | |
4 | {7}| 114 | 121 | 235 |- {7}| 5 | 1 | {61} = 18th prime
---+-----+-----+-----+-----+ | | |
5 | {13}| 122 | 135 | 257 |----- | |
---+-----+-----+-----+-----+ | |
6 | {19}| 136 | 155 | 291 |----------- |
---+-----+-----+-----+-----+ |
7 | {9}| 156 | 165 | 321 |----------------
---+-----+-----+-----+-----+
Δ Δ
139 286 Angka 56 dapat kita maknai sebagai 5 vs 6 pusaran pada distribusi bilangan² prima yang terbagi kedalam pola angka sembilan (9) dari id: 56 sd 65.
- 168 = d(1) + d(68) = d(1) + d(14) = d(114)
id: 6
---+-----+-----+-----+-----+
1 | 72 | 1 |{73} | 74 |----------------- 57. Flowchart <-- 7(111)
---+-----+-----+-----+-----+ | v |
2 | 20 |{74} | 94 |{168}|----------- |{157} >>{58} Sequence <--- 8(111)
---+-----+-----+-----+-----+ | {1} | v |
3 | 18 | 95 | 113 | 208 |----- | | 59. Grammar <---- 9(111)
---+-----+-----+-----+-----+ | {5} | | v |
4 | 7 |{114}| 121 | 235 |-{7} | | | 60. Channel<--6x10-->Δ
---+-----+-----+-----+-----+ | | | v |
5 | 13 | 122 | 135 | 257 |----- | |{61} >> 61. Route - Φ(61)-->{16}
---+-----+-----+-----+-----+ | | v |
6 | 19 | 136 | 155 | 291 |----------- | 62. Tree -- Φ(62)-->{26}
---+-----+-----+-----+-----+ | v |
7 | 9 |{156}|{165}| 321 |---------------- 63. Out --- Φ(63)-->{369}
---+-----+-----+-----+-----+Proses dari 55 ke 56 berlaku sebagai titik awal 57 ke 58 yang kita bahas di halaman ini. Karena formasi 111+3 ini mulai dari angka 2, totalnya repdigit, tepat di angka 7 yaitu 11x7 atau 77.
Dengan demikian skema 111 objek pada angka 12 akan menjadi basis ke 114 angka dasar. Sebagai gambaran tentang bagaimana kelanjutannya berikut saya jelaskan filosofinya.
Pada id: 58 diproses angka 70 pada format (70,30,100) dengan Δ14 kedalam 8 baris ke-5 sd -13 versus 8 kolom ke-3 sd ke-11 berujung 5 pusaran di titik (29,43,57,71,85).
- 60 - (85 - 29)/14 = 60 - 4 = 56
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{1} |{19}| - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 | 26*| - | 38 | - | - | - | - | - | 74*| - | - | - | 98*| 104*| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27*| - | 39 | - | - | - | - | - | 75*| - | - | - | 99*| 105*| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{5} | 23 |{29}| - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{7} | 25 | - | - |{43}| - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{9} | - | - | - | 45 | - |{57}| - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{11} | - | - | - | 47 | 53 | 59 | - |{71}| - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{13} | - | - | - | 49 | - | 61 | 67 | - | - |{85}| - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32*| 50*| - | 62 | 68*| - | - | 86*| - | - | - | - | - | 110*| - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
15 | - | - | 33*| 51*| - | 63 | 69*| - | - | 87*| - | - | - | - | - | 111*| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{18} | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{19} | 2 | {3}| 4 | {5}| 6 | {7}| 8 | {9}| 10 |{11}| 12 | 13 | 14 | 15 | 16 | 17 | 18 |{19}|
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|Pada id: 59 diproses 6 titik pusaran (51,61,71,81,91,101) dimana dari total Δ50 maka polarisasi di angka 71 membagi dengan Δ10 pada pusaran 51 ke 61 dan Δ40 pada pusaran 61 ke 101.
- 60 + (101-51)/10 = 60+5 = 65 = mirror 56
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{1} | 19 | - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
2 | 20 | 26*| - | 38 | - | - | - | - | - | 74*| - | - | - | 98*| 104*| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
3 | 21 | 27*| - | 39 | - | - | - | - | - | 75*| - | - | - | 99*| 105*| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{5} | 23 | 29 | - | 41 | - | - | - | - | - | 77 | - | - | - {101}| - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{7} | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - |{91}| 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{9} | - | - | - | 45 | - | 57 | - | - | - |{81}| - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{11} | - | - | - | 47 | 53 | 59 | - |{71}| - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108 | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{13} | - | - | - | 49 | - |{61}| 67 | - | - | 85 | - | - | - | - | - | 109 | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
14 | - | - | 32*| 50*| - | 62 | 68*| - | - | 86*| - | - | - | - | - | 110*| - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{15} | - | - | 33*|{51*} - | 63 | 69*| - | - | 87*| - | - | - | - | - | 111*| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106 | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107 | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+-----+-----+----+----+
{18} | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | - | - | - | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+=====+=====+====+====+
{19} | 2 | 3 | 4 | {5}| 6 | {7}| 8 | {9}| 10 |{11}| 12 |{13}| 14 |{15}| 16 | 17 | 18 |{19}|
|--------------------------------------------------------- 19¨ -----------------------------|
|--------------------------------------- 13¨ ---------------|
|------------- 7¨ ------------|
|-------- 5¨ -------|
|--- 2¨ --|Ketiga formasi ini yang membentuk Skema Projek sehingga merepresentasikan Sistem DNA yaitu berupa susunan kawat² melingkar seperti torus dengan bentuk yang dikenal dengan istilah trifoil.
Seperti sudah dijelaskan di halaman Pratinjau sistem pemetaan 18 vs 19 ini yang kita integrasikan seluruhnya dengan mengadopsi Metoda Quantum 6666 dari eQ19-Maps yang menerapkan Lisensi untuk mencantumkan kalimat ini dimanapun tempat dia digunakan:
The definite key to identify whether you use our concept is when there a kind of development item lies a unified assignment in hexagonal form by six (6) corresponding sets while each sets pick a combination of six (6) routes with a pairing of six (6) to six (6) of all channels.
Polanya akan nampak bila kita satukan semua hasil yang telah dibahas dimana angka 60 menjadi 10 dan 50 sebanyak dua (2) kali via pusaran di angka 30 sebanyak lima (5) kali.
- (30/(9+6))5 = 25 = 32
Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
1 | 3 | 1:1:0 | 2 | {60}| 40 | - | - | - | - | - | 102 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ 168
2 | 4 | 1:2:1 | 1 | {30}| 30 | 5 | - | - | - | - | 66 | {7}
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----
3 | 6 |*1:2:2 | 1 | {30}| 200 | 8 | 40 | {50}| - | - | 329 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ 618
4 | 6 |*1:3:3 | 1 | {30}| 200 | 8 | {10}| 40 | - | - | 289 | 12
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
5 | 5 | 1:3:4 | 1 | {30}| 8 | 40 | 4 | - | - | - | 83 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
6 | 3 |*1:3:5 | 30 | {30}| 5 | - | - | - | - | - | 65 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ 581
7 | 2 |*1:4:6 | 200 | 2 | - | - | - | - | - | - | 202 | {17}
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ Δ10
8 | 7 | 1:4:7 | 1 | {30}| 70 | {30}| 40 | {10}| {50}| - | 231 |
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========Perhatikan bahwa Format (70,30,100) dari Basis DNA dibelah menjadi (1,30,70,30,40,10,50). Ada angka 30 yang berulang merepresentasikan selisih Δ2 ke id: 32 itu urusannya naik dua (2) kali:
- π (Φ (329 + 289)) = π (Φ x 618) = π (1000) = 168
Kesimpulannya Basis DNA itu titik nol nya bukan bermula dari partikel melainkan energi diproses menjadi massa via crossing pada komposisi bilangan² prima di angka tujuhpuluh satu (71).
Dengan demikian proses pertama di id: 58 akan berada di angka 11 melalui skema pembelahan dari angka 57 ke formasi 5 dan 7 via Skema True Prime Pairs berikut ini:
- 18 + 43 = 61 = 18th prime
True Prime Pairs:
(5,7), (11,13), (17,19)
layer| i | f
-----+-----+---------
| 1 | 5
1 +-----+
| 2 | 7
-----+-----+--- } 36 » 6®
| 3 | 11
2 +-----+
| 4 | 13
-----+-----+---------
| 5 | 17
3 +-----+ } 36 » 6®
| 6 | 19
-----+-----+---------
|------------------------- Skema-12 ------------------------|
|------------ 6¤ -------------|------------- 6¤ ------------|
|--------------------------- 192 ---------------------------|
|---- {23} ----|---- {49} ----|-- {29} -|--{30} --|-- 61 ---|
+----+----+----+----+----+----+----+----+----+----+----+----+
| 5 | 7 |{11}| 13 | 17 | 19 | 17 | 12 |{11}| 19 | 18 | 43 |
+----+----+----+----+----+----+----+----+----+----+----+----+
|--- 12 --|----- 41 -----| 19 |--------- {77} ---------|{43}|
|--------- 5¤ ---------|------------ {96} -----------|{43}|
|--------- {53} ---------|-------------- {139} -------------|
|--------- 5¤ ---------|--------------- 7¤ ---------------|
|------- Skema-23 -------|------------- Skema-34 -----------|Skema ini memunculkan formasi 11 ke 77 hingga berada tepat diantara angka 19 dan 43 sebagai titik pusaran ke-1 dan -2 dari Minor Hexagon.
Korelasi peran signifikan dari 11 ke 77 dengan sistem alamiah ada pada pembentukan kromosom (xX, xY) dimana duapuluh dua (22) diformat secara simetris (22,23,32) via limapuluh lima (55):
- 22 + 23 + 32 = 22 + 55 = (2,5)" = 77
Ini adalah bagan kromosom yang asli dari presentasi berjudul: Genetics yang dirilis berdasarkan hasil temuan tahun 1955 oleh Joe Hin Tjio, seorang ilmuwan yang lahir dan besar di Indonesia.
The number of human chromosomes was published in 1923 by Theophilus Painter. By inspection through the microscope, he counted 24 pairs, which would mean 48 chromosomes. His error was copied by others and it was not until 1956 that the true number, 46, was determined by Indonesia-born cytogeneticist Joe Hin Tjio. - (Wikipedia)
Dia inilah yang berhasil membuktikan bahwa kromosom manusia terdiri dari 23 pasang, bukan 24 pasang seperti yang diyakini para ahli² genetika dunia pada saat itu sejak lama.
Pada halaman Pratinjau kita sudah bahas proyeksi angka 114 dari formasi (70,30,100) via angka 13 ke 43 yang terbagi dalam sembilan (9) polarisasi angka dua (2) versus 30 ke 60 berikut ini:
- 109 + 30 + 29 = 168 = π(1000)
Scheme 13:9
===========
(1){1}-7: 7’
(1){8}-13: 6‘
(1)14-{19}: 6‘
------------- 6+6 -------
(2)20-24: 5’ |
(2)25-{29}: 5’ |
------------ 5+5 -------
(3)30-36: 7:{70,30,100}|
------------ |
(4)37-48: 12• --- |
(5)49-59: 11° | |
--}30° 30• |
(6)60-78: 19° | |
(7)79-96: 18• --- |
-------------- |
(8)97-109: 13 |
(9)110-139:{30}=5x6 <----
--
{43}Skema dari 12 repository utama dapat dilihat pada skema (1,2,3) vs (4,2) dari Basis DNA yaitu diantara id: 29 ke 49 sedangkan prosesnya oleh id: 49 ke 78.
#8 |--------- 6® ----------|---------- 6® ------------|
| 1 |-------------- 77 = 4² + 5² + 6² -------------|
------+---|---+---+---+---+---+---+---+---+----+----+----+
repo |{1}|{2}| 3 |{4}| 5 | 6 | 7 | 8 | 9 | 10 | 11 |{12}| ∑ 1,77
------+---|---+---+---+---+---+---+---+---+----+----+----+
user | 7 | - | - | - | - | 7 | 8 | - | - | 8 | 8 | 3 | (1,2,3)
------+---|---+---+---+---+---+---+---+---+----+----+----+--------- ∑ 7,78
main | - |{9}| 7 |{9}| 6 | - | - | 8 | 5 | - | - | - | (4,2)
------+---|---+---+---+---+---+---+---+---+----+----+----+
Δ | Δ Δ | Δ | Δ | Δ Δ | Δ
Φ17|Φ29 Φ49|Φ56|Φ67|Φ78 96-99| 100 -{123}({24})
|--- A,T,G,C ---| | └── 100 - 103 (4x) » 100
Δ 2x2 = 4x |------- 2x3 = 6x -------| └── 104 - 109 (6x) » 30
{98} | └── 110 - 123 (14x)» 70Pada 10 baris pertama mewakili prinsip dasar dari projek. Skemanya diambil berdasarkan DOM Object via code html pada halaman dari repository utama yaitu angka satu (1) dan dua (2).
- β(10,13,15,18) = 289 + 95 + 126 + 61 = 285 + 286 = 571
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
5 | 5 | 1:3:4 | 20 | 21 | 22 | 23 | 24 | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
6 | 3 |*1:3:5 | 25 | 26 | 27 | - | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
7 | 2 |*1:4:6 | 28 | 29 | - | - | - | - | - | - | ? |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
8 | 7 | 1:4:7 | 30 | 31 | 32 | 33 | 34 | 35 | {36}| - | ? |
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
9 | 6 |*1:4:8 | 37 | 38 | 39 | 40 | 41 | {42}| - | - | 329 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ {618}
10 | {6} |*1:4:9 | 43 | 44 | 45 | 46 | 47 | {48}| - | - | 289 |
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========Dari konfigurasi di bawah ini Anda bisa lihat bahwa konfigurasi bilangan² prima memecah 7 ke 17 dimana selisih keduanya tepat di angka 9 ke 19 dan 19 ke 29 atau sepuluh (10).
Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
1 | 3 | 1:1:0 | 2 | {60}| 40 | - | - | - | - | - | 102 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ 168
2 | 4 | 1:2:1 | 1 | 30 | 30 | 5 | - | - | - | - | 66 | 7
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----
3 | 6 |*1:2:2 | 1 | 30 | 200 | 8 | 40 | {50}| - | - | 329 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ {618}
4 | 6 |*1:3:3 | 1 | 30 | 200 | 8 | {10}| 40 | - | - | 289 | 12
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
5 | 5 | 1:3:4 | 1 | 30 | 8 | 40 | 4 | - | - | - | 83 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
6 | 3 |*1:3:5 | 30 | 30 | 5 | - | - | - | - | - | 65 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ 581
7 | 2 |*1:4:6 | 200 | 2 | - | - | - | - | - | - | 202 | 17
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
8 | 7 | 1:4:7 | 1 | 30 | 70 | 30 | 40 | {10}| {50}| - | 231 |
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
9 | 6 |*1:4:8 | 1 | 30 | 200 | 8 | 40 | {50}| - | - | 329 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ {618}
10 | {6} |*1:4:9 | 1 | 30 | 200 | 8 | {10}| 40 | - | - | 289 | 12
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
168 --> 581 | 1985
Φ 185Korelasi antara Bagan Flowchart dan Sequence dapat dilihat dari kedua gambar dibawah dimana Flowchart adalah proses dari 10 bilangan prima pertama sampai duapuluh sembilan (29).
Bagan Sequence akan memunculkan id mulai dari tigapuluh (30) dimana representasi dari tujuh (7) id dari Basis DNA akan teralokasi pada id 30 sd 36.
Proses yang dilakukan pada tahap berikutnya akan menyertakan pola dari semua unit dan objek dari Prime 114 yaitu proses dari Skema ke Mapping secara keseluruhan.
Sesuai seperti yang sudah kita bahas angka 58 ke 59 ini akan mengantarkan kita ke formasi dari angka enampuluh (60) yang merupakan titik mula proses angka 85 ke 95 dan 102 ke 168.
- 2 + 60 + 40 + 66 = 102 + 66 = 168
Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
5 | 5 | 1:3:4 | 1 | 30 | 8 | 40 | 4 | - | - | - | 83 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
6 | 3 |*1:3:5 | 30 | 30 | 5 | - | - | - | - | - | 65 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ 581
7 | 2 |*1:4:6 | 200 | 2 | - | - | - | - | - | - | 202 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
8 | 7 | 1:4:7 | 1 | 30 | 70 | 30 | {40}|{10} | {50}| - |{231}|
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----Angka 168 ini merupakan bagian dari angka 786 yaitu 7 dari 19 angka pada baris awal dimana 12 sisanya yaitu dari posisi 8 ke 19 penjumlahannya akan jatuh di angka 618.
- 168 + 618 = 786
|------------ 36' --------------|----------------------------36' ----------------------------|
| 19' | 17' | 13' | 11' | 7' | 5' |
+---+----+----+---+----+----+---+---+----+-----+----+----+----+----+----+-----+----+----+----+
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 |
+---+----+----+---+----+----+---+---+----+-----+----+----+----+----+----+-----+----+----+----+
| 2 | 60 | 40 | 1 | 30 | 30 | 5 | 1 | 30 | 200 | 8 | 40 | 50 | 1 | 30 | 200 | 8 | 10 | 40 |
+---+----+----+---+----+----+---+---+----+-----+----+----+----+----+----+-----+----+----+----+
| ° |ΔΔΔΔ ΦΦ | • ΔΔ ΔΔ ¤ | • ΔΔ ΦΦΦ Φ ΦΦ ¤¤¤¤| • ΔΔ ΦΦΦ Φ ¤¤ ΦΦ |
|---- 102 ---|----- 66 ------|-------- 329 = 7 x 47 -------|- 289 = (8+9)² = 2 & (2³+9²) -|
|--2x3x(8+9)--|--- 2x3x(2+9) ---|---- (1+2) & (2x9)+(2+9) ----|------ 2 & (8x9)+(8+9) -------|
|-------- 168 = π(1000) --------|------ 1229 = π(10000) ------|------ π(89²) = 1000 ---------|
|-------- 168 = π(618xΦ) -------|----- 618 = 1000/Φ = 1000x1000/1618 = 10^6/(2x8)&(2x9) -----|Angka 618 yang mewakili transformasi dari 61 ke 68 ditempatkan di baris 9 dan 10 sehingga kita dapat melakukan pembagian objek pada tahap berikutnya.
- 1 + 618 = 619 = 114th prime
Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
9 | 6 |*1:4:8 | 1 | 30 | 200 | 8 | 40 | {50}| - | - | 329 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ {618}
10 | {6} |*1:4:9 | 1 | 30 | 200 | 8 | 10 | {40}| - | - | 289 |
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========Dengan demikian skema berikutnya kita akan mulai dari formasi angka enampuluh satu (61) via pasangan prime ke-2 dari True Prime Pairs yaitu 11 dan 13.
- 2 x 11 x 13 = 22 x 13 = 286 = d(16) = d(61) = d(241)
Scheme-139:
i | Φ | # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ∑° | ∑
====+=====+=======+=====+=====+=====+=====+=====+=====+=====+=====+=====+========
11 | 3 | 2:1:0 | 40 | 30 | 20 | - | - | - | - | - | 90 | 3Φ
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+ |
12 | 3 | 2:2:1 | 10 | 6 | {40}| - | - | - | - | - | 56 | 241
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+
13 | 5 |*2:2:2 | 1 | 30 | 4 | 10 | {50}| - | - | - | 95 |
----+-----+-------+-----+-----+-----+-----+-----+-----+-----+-----+-----+-----Semuanya ini akan berujung di angka 10143 dimana via d(10) dan d(17) kita akan sampai di d(18) sehingga akan kembali berlaku sebagai ujung Polar 18 vs 19 dari komposisi bilangan² prima.
Dari uraian di atas Anda bisa lihat bahwa transformasi yang signifikan ada pada tiga (3) pasangan prima dari True Prime Pairs dimana kita juga akan jumpai Skema 23 Kromosom.
Description
===========
Getting result within a huge package (5 to 19) by spreading (11)
the untouched objects (7) and tunneling (13) them in to a definite scheme (17).
Compositions
============
+-----+-----+-----+-----+-----+-----+-----+-----+ ----- 62 - 63
| 102 | 1 | - | - | - | - | - | 11 | 114 5¨ » Buka Toko
+-----+-----+-----+-----+-----+-----+-----+-----+ ----- 63 - 64
| - | - | 200 | - | - | - | - | {47}| 247 7¨ » Stok Barang
+-----+-----+-----+-----+-----+-----+-----+-----+ ----- 65 - 66
| - | - | - | 40 | 1 | - | - | 98 | 139 11¨ » Merchant Centre
+-----+-----+-----+-----+-----+-----+-----+-----+ ----- 66 - 67
| - | - | - | - | - | 200 | - | 86 | 286 13¨ » Peluang Terbaik
+-----+-----+-----+-----+-----+-----+-----+-----+ ---- 68 - 69
| - | - | - | - | - | - | 50 | 107 | 157 17¨ » Portfolio
+-----+-----+-----+-----+-----+-----+-----+-----+ ----- 69 - 71
| 66 | 30 | 8 | 50 | 30 | 8 | - | 594 | 786 19¨ » Network
+-----+-----+-----+-----+-----+-----+-----+-----+ ---------------
168 | 31 208 {90}| 31 208 50 | 943 | 1729 17 - 29
Δ
77|78Disini berlaku Skema in-out persisnya adalah pada angka 5 ke 17 dimana 5x vektor 231 dari (2,3) yang berupa 7 objek dari format (70,30,100) ada di baris 8 dengan bobot sama yaitu 231.
Dengan skema ini maka angka 7 dari 17 objek yang memiliki jumlah 231 akan bertransformasi ke Skema-23 via 42 ke 43 tepat di vektor 278 pada indek ke-23 diantara vektor 70 dan 100.
True Prime Vektors ζ(s):
(2,3), (29,89), (36,68), (72,42), (100,50), (2,3), (29,89), ...infinity
----------------------+-----+-----+-----+ ---
7 --------- 1,2:1| 1 | 30 | 40 | 71 (2,3) ‹-------------@---- |
| +-----+-----+-----+-----+ | |
| 8 ‹------ 3:2| 1 | 30 | 40 | 90 | 161 (7) ‹--- | 5¨
| | +-----+-----+-----+-----+ | | |
| | 6 ‹-- 4,6:3| 1 | 30 | 200 | 231 (10,11,12) ‹--|--- | |
| | | +-----+-----+-----+-----+ | | | ---
--|--|-----» 7:4| 1 | 30 | 40 | 200 | 271 (13) --› | {5®} | |
| | +-----+-----+-----+-----+ | | |
--|---› 8,9:5| 1 | 30 | 200 | 231 (14,15) ---------› | 7¨
289 | +-----+-----+-----+-----+-----+ | |
| ----› 10:6| 20 | 5 | 10 | 70 | 90 | 195 (19) --› Φ | {6®} |
--------------------+-----+-----+-----+-----+-----+ | ---
67 --------› 11:7| 9 | 5 | 14 (20) --------› ¤ | |
| +-----+-----+-----+ | |
| 78 ‹----- 12:8| 9 | 60 | 40 | 109 (26) «------------ | 11¨
| | +-----+-----+-----+ | | |
| | 86‹--- 13:9| 9 | 60 | 69 (27) «--- Δ (Rep Fork) | 2® | |
| | | +-----+-----+-----+ | | ---
| | ---› 14:10| 9 | 60 | 40 | 109 (28) ------------ | |
| | +-----+-----+-----+ | |
| ---› 15,18:11| 1 | 30 | 40 | 71 (29,30,31,32) ------------ 13¨
329 | +-----+-----+-----+ |
| ‹--------- 19:12| 10 | 60 |{70} (36) ‹-------------------- Φ |
-------------------+-----+-----+ ---
786 ‹------- 20:13| 90 | 90 (38) ‹-------------- ¤ |
| +-----+-----+ |
| 618 ‹- 21,22:14| 8 | 40 | 48 (40,41) ‹---------------------- {17¨}
| | +-----+-----+-----+-----+-----+ | |
| | 594 ‹{23}:15| 8 | 40 | {70}| 60 |{100}|{278} ({42}) «-- |{6'®} |
| | | +-----+-----+-----+-----+-----+ | | ---
--|--|-»24,27:16| 8 | 40 | 48 (43,44,45,46) ------------|---- |
| | +-----+-----+ | |
--|---› 28:17| 100 |{100} (50) --------------------------» 19¨
{168} | +-----+ |
| 102 -› 29:18| 50 | 50(68) ---------> Δ |
----------------------+-----+ ---Sekarang kita urut berdasarkan jumlah faktor. Misal angka pertama yaitu 71 adalah 3 faktor, yang kedua yaitu 161 adalah 4 faktor dst maka kita akan dapatkan 14 kelompok berikut ini:
- Φ(11,13) = (114 - 10²) + 13 = 27
1729 = 7 x 13 x 19
1729 / 7 = 13 x 19 = 247
1729 = 7 x 13 x 19
7 + 13 = 20 = d(2)
└── 2 x 19 = 38 {Φ58}
Δ
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ 571
| {1}| 2 | 3 | 4 | 5 | {6}| {7}| 8 | 9 | 10 | 11 | 12 | 13 | 14 | Δ
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ 286
| {3}| {4}| 3 | 4 | 5 | 2 | 3 | 2 | 2 | 1 | 2 | 5 | 1 | 1 | 38 Δ
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+---- } {285}
| 3 | 8 | 9 | 16 | 25 |{12}|{21}| 16 | 18 | 10 | 22 | 60 |{13}|{14}|{247}
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
|-- 38 ---| |-- 33 ---| |-- {27}--|Dari susunan ini kita dapatkan jumlah seluruh vektor dengan urutannya di angka 247 dimana via angka satu (1) menjadikan 10 terkoneksi dengan 13 dan 14 ke angka duapuluh tujuh (27).
14=2*7->2147=19*113->192147113=857*224209. Note that each new semiprime begins and ends with the ordered factors of the previous one. Can you find a larger chain? See for 139.
Jika kita jumlahkan angka 38 dan 247 muncul angka 285 dari blok objek 96. Dari angka ini tentu Anda paham korelasinya dengan id: 58 ke formasi angka 8 dan 5 yang dibahas di awal.
Sekian.
SALAM Sukses!
© Chetabahana Project
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